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Likurg_2 [28]
3 years ago
14

What is the weight in grams of 3.36 x 10^23 molecules of copper sulfate

Chemistry
1 answer:
Llana [10]3 years ago
5 0

Answer:

m=89.0g

Explanation:

Hello!

In this case, since we are given the formula units (molecules) of copper sulfate, it is possible to compute the moles of this compound via the Avogadro's number:

n=3.36x10^{23}molecules*\frac{1mol}{6.022x10^{23}molecules}\\\\n=0.558mol

Now, given the molar mass of copper sulfate which is 159.60 g/mol, the required mass in grams turns out:

m=0.558mol*\frac{159.60g}{1mol}\\\\m=89.0g

Best regards!

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