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lianna [129]
2 years ago
10

Is ok2 gas a element compound or homogeneous or heterogeneous mixture?

Chemistry
1 answer:
ivolga24 [154]2 years ago
4 0
I'm guessing you mean O2 gas? This is an elemental compound. It can't be a mixture because it is composed of only 1 element. Hope I helped!
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The amount of calories you weight
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Which of the following provides cell support in an animal cell? A. microtubule B. mitochondria C. lysosomes D. vacuole
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Answer:

D.

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Explanation:

Hope this helps:)

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3 years ago
Describe what half-life is.<br> answer in a paragraph please.
dangina [55]

Half-life is defined as the quantity to reduce to half of its initial value.

Explanation:

The term half-life is generally used in nuclear physics which describes how long a stable atom can survive a radioactive decay or how quickly an unstable stable atom can undergo radioactive decay. Half-life is a constant and does not have any units.

<u>The formula to calculate half-life: </u>

N(t) = \bold{N_{0} e^{-\lambda t}}

Here N(t) is the quantity which is “not decayed”.

N_0 is the “initial quantity” of the substance.

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3 years ago
Christopher conducts an experiment in which he tests how much sugar dissolves at different temperatures of water. One step requi
a_sh-v [17]

Answer:

305.65 K

Explanation:

Celsius to Kelvin => + 273.15

32.5 + 273.15

= 305.65 K

7 0
2 years ago
The heat required to raise the temperature of 12g of water from 16 C to 21 C is:
NemiM [27]

Answer:

The heat required to raise the temperature of 12g of water from 16 C to 21 C is 60 cal.

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

There is a direct proportional relationship between heat and temperature. The constant of proportionality depends on the substance that constitutes the body as on its mass, and is the product of the specific heat by the mass of the body. So, the equation that allows calculating heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

  • Q=?
  • c= 4.186 \frac{J}{g*C}
  • m= 12 g
  • ΔT=Tfinal - Tinitial= 21 °C - 16°C= 5 °C

Replacing:

Q= 4.186 \frac{J}{g*C} *12 g *5 °C

Solving:

Q=251.16 J

Since 1 J is equal to 0.2388 cal, then the following rule of three can be applied: if 1 J is equal to 0.2388 cal, then 251.16 J to how many cal are?

cal=\frac{251.16 J * 0.2388 cal}{1 J}

cal= 59.98 ≅ 60

<u><em>The heat required to raise the temperature of 12g of water from 16 C to 21 C is 60 cal.</em></u>

3 0
2 years ago
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