Answer:
0_10 =0_2
Step-by-step explanation:
Convert the following to base 2:
0_10
Hint: | Starting with zero, raise 2 to increasingly larger integer powers until the result exceeds 0.
Determine the powers of 2 that will be used as the places of the digits in the base-2 representation of 0:
Power | \!\(\*SuperscriptBox[\(Base\), \(Power\)]\) | Place value
0 | 2^0 | 1
Hint: | The powers of 2 (in ascending order) are associated with the places from right to left.
Label each place of the base-2 representation of 0 with the appropriate power of 2:
Place | | | 2^0 |
| | | ↓ |
0_10 | = | ( | __ | )_(_2)
Hint: | Divide 0 by 2 and find the remainder. The remainder is the first digit.
Determine the value of 0 in base 2:
0/2=0 with remainder 0
Place | | | 2^0 |
| | | ↓ |
0_10 | = | ( | 0 | )_(_2)
Hint: | Express 0_10 in base 2.
The number 0_10 is equivalent to 0_2 in base 2.
Answer: 0_10 =0_2
Answer:
We have:
x < 4 AND x > a.
if a = 4 and we use an "or" instead of the "and" we have:
x < 4 or x > 4.
This is:
"x is larger than 4 or smaller than 4."
Then the solution of this is all the real numbers except the value x = 4.
The set of solutions can be written as:
{xI x ∈ R \ [4]}
Where this reads:
"x belongs to the set of the reals minus the number 4".
Or we also could write it as:
x ∈ (-∞, 4) ∪ (4, ∞)
Where we have two open ends in the "4" side, so the value x = 4 does not belong to that set.
Answer:
The answer is 7.
Step-by-step explanation:
You have to substitute the value of x into the function :
I would think 0.10 would be the answer
Answer: x=1/2
she was wrong, it's supposed to be
Step-by-step explanation: 8(x−3)+7=2x(4−17)
Step 1: Simplify both sides of the equation.
8(x−3)+7=2x(4−17)
(8)(x)+(8)(−3)+7=2x(4−17)(Distribute)
8x+−24+7=−26x
(8x)+(−24+7)=−26x(Combine Like Terms)
8x+−17=−26x
8x−17=−26x
Step 2: Add 26x to both sides.
8x−17+26x=−26x+26x
34x−17=0
Step 3: Add 17 to both sides.
34x−17+17=0+17
34x=17
Step 4: Divide both sides by 34.
34x/34=17/34 x=1/2
