Ammonia can be determined spectrophotometrically by reaction with phenol in the presence of hypochlorite (OCl−):
1 answer:
Answer:
See explaination
Explanation:
Molar absorptivity, also known as the molar extinction coefficient, is a measure of how well a chemical species absorbs a given wavelength of light.
It is commonly used in chemistry and should not be confused with the extinction coefficient, which is used more often in physics.
Please kindly check attachment for the step by step solution of the given problem.
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CuCl2 is Dichloride Copper, or Copper II Chloride.
In this Molecule, there is 1 atom of Copper for every 2 atoms of Chlorine.
If you go to the periodic table, you'll see that copper has a mass of 63.5 amu, and the chlorine 35.45 amu.
Which mean that the mass of CuCl2 is 63.5 + 35.45*2 = 63.5 + 70.9 = 134.4 g/mol.
Then, you find the ration of the mass of each atom and multiply by 100.
Ratio of Copper:
and you get about 47.2%
Ration of chlorice (Cl2):
and you get about 52.8%.
So, the percent composition of CuCl2 is 47.2% of Copper and 52.8% of chlorine.
Hope this Helps :)
In this Molecule, there is 1 atom of Copper for every 2 atoms of Chlorine.
If you go to the periodic table, you'll see that copper has a mass of 63.5 amu, and the chlorine 35.45 amu.
Which mean that the mass of CuCl2 is 63.5 + 35.45*2 = 63.5 + 70.9 = 134.4 g/mol.
Then, you find the ration of the mass of each atom and multiply by 100.
Ratio of Copper:
Ration of chlorice (Cl2):
So, the percent composition of CuCl2 is 47.2% of Copper and 52.8% of chlorine.
Hope this Helps :)
Answer:
22.44°C will be the final temperature of the water.
Explanation:
Heat lost by tin will be equal to heat gained by the water
Mass of tin =
Specific heat capacity of tin =
Initial temperature of the tin =
Final temperature = =T
Mass of water=
Specific heat capacity of water=
Initial temperature of the water =
Final temperature of water = =T
On substituting all values:
we get, T = 22.44°C
22.44°C will be the final temperature of the water.
Conjugate base of Propanoic acid ( is propanoate where -COOH group gets converted to -CO
. The structure of conjugate base of Propanoic acid is shown in the diagram.
The above which 90% of the compound will be in this conjugate base form can be determined using Henderson's equation as propanoic acid is weak acid and it can form buffer solution on reaction with strong base.
=
+ log
=4.9+log
=5.85
As 90% conjugate base is present, so propanoic acid present 10%.
