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3 years ago

Ammonia can be determined spectrophotometrically by reaction with phenol in the presence of hypochlorite (OCl−):

Chemistry

1 answer:

Valentin [98]3 years ago

7 0

Answer:

See explaination

Explanation:

Molar absorptivity, also known as the molar extinction coefficient, is a measure of how well a chemical species absorbs a given wavelength of light.

It is commonly used in chemistry and should not be confused with the extinction coefficient, which is used more often in physics.

Please kindly check attachment for the step by step solution of the given problem.

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Three of the primary components of air are

Darya [45]

Answer:

125.681 torr

Explanation:

The formula to calculate the partial pressure of oxygen:

P(O2) = Pcommon - PCO2 - PN2

1 atm = 760 torr

Therefore you need to find the partial pressure of oxygen:

P(O2) = 760 torr -0.285 torr - 634.034 torr =130.013 torr

- Hope that helped!

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3 years ago

A student placed 15.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then

Ede4ka [16]

Answer: The mass of glucose in final solution is 1.085 grams

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$ ......(1)

Given mass of glucose = 15.5 g

Molar mass of glucose = 180.2 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$\text{Molarity of glucose solution}=\frac{15.5\times 1000}{180.2\times 100}\\\\\text{Molarity of glucose solution}=0.860M$

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated glucose solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted glucose solution

We are given:

$M_1=0.860M\\V_1=35.0mL\\M_2=?M\\V_2=0.500L=500mL$

Putting values in above equation, we get:

$0.860\times 35.0=M_2\times 500\\\\M_2=\frac{0.860\times 35.0}{500}=0.0602M$

Now, calculating the mass of glucose by using equation 1, we get:

Molarity of glucose solution = 0.0602 M

Molar mass of glucose = 180.2 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$0.0602=\frac{\text{Mass of glucose solution}\times 1000}{180.2\times 100}\\\\\text{Mass of glucose solution}=\frac{0.0602\times 180.2\times 100}{1000}=1.085g$

Hence, the mass of glucose in final solution is 1.085 grams

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3 years ago

Tiffany was investing how fast it took Hayden to react to different sounds. Identify the independent variable.

Hatshy [7]

Answer:

The different sounds

Explanation:

since it can not be changed

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3 years ago

In some regions of the world, forests are cut down and then burned to create room for farmland. How might this local environment

UkoKoshka [18]

The answer is D.

Explanation

Without trees, no carbon dioxide will be released into the air. It would not raise oxygen levels, and it wouldn’t effect rising sea levels.

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3 years ago

Read 2 more answers

Name three sources of atmospheric carbon dioxide.

timurjin [86]

Answer:

Natural sources include decomposition, ocean release and respiration. Human sources come from activities like cement production, deforestation as well as the burning of fossil fuels like coal, oil and natural gas.

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3 years ago

Ammonia can be determined spectrophotometrically by reaction with phenol in the presence of hypochlorite (OCl−):

Ammonia can be determined spectrophotometrically by reaction with phenol in the presence of hypochlorite (OCl−):