How much work did he do if he traveled 20 meters?

A 110 n force and a 55 n force both act on an object point p. the 110 n force acts at 90 degrees. the 55 n force acts at 0 degre

ss7ja [257]

To determine the magnitude and the direction of the resultant force, we assume that the forces are in XY coordinate plane and the angles that are given are from the x axis.

The 110 N force is said to act at 90 deg which means it is along the Y axis. The 55 N force is said to act at 0 deg which means it is along the X axis. so, a right angle is made by the two forces. Thus, the

X component of the resultant force = 55 N 
Y component of the resultant force = 110 N 
Magnitude of the resultant force would be calculated as follows:
R = √(Fx^2 + Fy^2)
R = √(55^2 + 110^2) 
R = √(15125) 
R = 123 N 
The resultant force would have its terminal side in the x-axis. We calculate angle θ as follows:

tan θ = Fy/Fx 
tan θ = 110 N /55 N = 2
θ = arctan(2)
θ = 63.4 degrees
Therefore, the magnitude of the resultant force is 123 N and the direction would be at an angle of 63.4 degrees.

5 0

4 years ago

Jack and Jill exercise in a 25.0 m long swimming pool. Jack swims 9 lengths of the pool in 156.9 s ( 2 min and 36.9 s ) , wherea

Leya [2.2K]

Answer:

Jill average velocity is 0

Jack average velocity is 0.159337

Jill average speed = 1.593372

Jack average speed = 1.434034

Explanation:

given data

long swimming pool = 25.0 m

9 lengths of the pool = 156.9 s ( 2 min and 36.9 s )

10 lengths = same time interval

to find out

average velocity and average speed

solution

we know that average velocity that is express as

average velocity = $\frac{displacement}{time}$ .....................1

Jill come back where she start

so here velocity will be = 0

and

Jack ends up on the other end of pool

so average velocity = $\frac{25}{156.9}$

average velocity = 0.159337

now we get here average speed that is express as

average speed = $\frac{distance}{time}$ .............2

jack speed = 9 × $\frac{25}{156.9}$

jack speed = 1.434034

and

Jill speed = 10 × $\frac{25}{156.9}$

Jill speed = 1.593372

5 0

4 years ago

What happens to parallel light rays that strike a concave lens?

zhenek [66]

Due to the shape of the lens , parallel rays will be deviated

5 0

3 years ago

Read 2 more answers

How is a cold air mass similar to a mountain range as to the effect on a warm air mass?

Fittoniya [83]

Different types of fronts produce different patterns of weather. When a cold, dense air mass pushes warmer air, it produces a cold front. A cold front can turn a heat wave into normal summer weather or turn cold winter air into very cold weather. Cold fronts often produce tall cumulonimbus clouds.

8 0

4 years ago

If a truck is heading south at a velocity of 90m/s for 10 seconds how far did it travel?

RoseWind [281]

Answer:

Truck will be at a distance of 720 m

Explanation:

Speed of the truck is given as 90 m/sec

Time for which truck travel t = 10 seconds

We have to find the distance that how much truck travel in 8 sec with speed of 90 m/sec

We know that distance is given by $distance=velocity\times time$

So distance traveled by truck in 8 sec will be equal to $=90\times 8 =720m$

So truck will be at a distance of 720 m

3 0

4 years ago