Answer:
the normality of the given solution is 0.0755 N
Explanation:
The computation of the normality of the given solution is shown below:
Here we have to realize the two sodiums ions per carbonate ion i.e.
N = 0.321g Na_2CO_3 × (1mol ÷ 105.99g)×(2eq ÷ 1mol)
= 0.1886eq ÷ 0.2500L
= 0.0755 N
Hence, the normality of the given solution is 0.0755 N
Carbon, helium, and sodium are monoatomic elements.
Hydrogen, iodine, and oxygen are diatomic elements.
Answer:
Farthest from the carbonyl carbon.
Explanation:
Reference carbon that determined the absolute D and L configuration is located farthest from the carbonyl carbon.
In other words, reference carbon is that assymentric carbon which is located farthest from the carbolyl carbon and has configuration similar to D- or L-glyceraldehyde isomers.
D and L configuration is decided by the direction of -OH group attached to the reference carbon.
In L-isomer, -OH group is attached to the left side of the reference carbon and in D-isomer, -OH group is attached to the right side of the reference carbon.
Answer:
there are 2.2 moles of Li in 15 grams of Li
Answer:
Na₂O will also form a brittle ionic compound.
Explanation:
Sodium is located in the same group as Potassium: Alkali Metals. This is because both elements have similar chemical properties. In term of their electronegativity, both elements are very close. Na has an electronegativity of 0.93, while K has an electronegativity of 0.82. This makes both ideal elements to create ionic compounds with Oxygen.
