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3 years ago

A 0.5 kg ball moves in a circle that is 0.4 m in radius at a speed of 4.0 m/s. Calculate the force exerted on the ball.

Physics

1 answer:

blsea [12.9K]3 years ago

5 0

Answer:

Explanation:

Given a ball of mass m= 0.5kg

The ball moves in as circle of radius r= 0.4m

Speed of the ball is v = 4m/s

Centripetal force is exerted on ball and it is given as

Fc = m•ac

ac is centripetal acceleration and it is given as

ac = v²/r

Then,

Fc = mv²/r

Fc = 0.5 × 4²/0.4

Fc = 20N.

The force exerted on the ball is 20N

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zimovet [89]

Answer:

2*10^-5

Explanation:

B=IL

I=B/L

I=0.0020*10^-4/10

I=2*10^5

6 0

3 years ago

susan and joe push a table 18 meters down a hall by exerting a force of 200 newtons (n). what is the total amount of work done o

prisoha [69]

Answer:

3600joules

Explanation:

formula :W=FS

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S=displacement moved in the direction of force (m)

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3 0

2 years ago

A 4.50-kg wheel that is 34.5 cm in diametet rotates through an angle of 13.8 rad as it slows down uniformly from 22.0 rad/s to 1

lisabon 2012 [21]

Answer:

$\alpha =10.93radian/sec^2$

Explanation:

We have given given the final angular velocity $\omega _{final}=13.5rad/sec$

And $\omega _{initial}=22rad/sec$

Displacement $\Theta =13.8radian$

We have to find the angular acceleration $\alpha$

According to law of motion $\omega _{final}^2=\omega _{initial}^2+2\alpha \Theta$

So $13.5^2=22^2+2\times \alpha \times 13.8$

$\alpha =-10.93radian/sec^2$

In question we have tell about magnitude only so $\alpha =10.93radian/sec^2$

4 0

3 years ago

A small diameter lead ball and a large diameter rubber ball are dropped from a tower. The balls hit the ground at the same time.

solmaris [256]

This demonstration doesn't tell anything about the force of gravity.
But it does demonstrate that the acceleration of gravity is the same
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7 0

3 years ago

Â (a) How long can you rapidly climb stairs (116/min) on the 166.0 kcal of energy in a 200g apple? (b) How many flights is this

adoni [48]

Answer:

a) It will take you 16.94 min to climb the stairs.

b) The numbers of flights are 123 flights.

Explanation:

a) Let the energy consumption while climbing the stairs be 685 W in kcal/min is given by:

rate of energy consumption = (685 W)×[(0.01433kcal/min)/1 W]

= 9.81605 kcal/min

the time it takes to climb the stairs is given by:

t = E/P

= (166.0 kcal)/(9.8 kcal/min)

= 16.94 min

Therefore, it will take you 16.94 min to climb the stairs.

b) Given t is the time it takes to climb stairs and N is the number of stairs to climb per min, then the number of stairs is:

n = t×N

= (16.94)×(116)

= 1965 stairs

given the number of stairs each flight as N1, then the number of flights is given by:

flights = n/N1

= (1965)/(16)

= 123 flights

Therefore, the numbers of flights are 123 flights.

7 0

3 years ago