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podryga [215]
3 years ago
15

What are two ways that substances can pass through a cell membrane out of the cell

Chemistry
1 answer:
Paha777 [63]3 years ago
3 0

Answer:

Passive transport, and Active transport

Explanation:

Do u need an explanation?

If so you can tell me and I'll edit it

Hope this helped a little!

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When 16.3 g of magnesium and 4.52 g of oxygen gas react, how many grams of magnesium oxide will be formed? Identify the limiting
Tanzania [10]

Answer:

22.77 g.

he limiting reactant is O₂, and the excess reactant is Mg.

Explanation:

  • From the balanced reaction:

<em>Mg + 1/2O₂ → MgO,</em>

1.0 mole of Mg reacts with 0.5 mole of oxygen to produce 1.0 mole of MgO.

  • We need to calculate the no. of moles of (16.3 g) of Mg and (4.52 g) of oxygen:

no. of moles of Mg = mass/molar mass = (16.3 g)/(24.3 g/mol) = 0.6708 mol.

no. of moles of O₂ = mass/molar mass = (4.52 g)/(16.0 g/mol) = 0.2825 mol.

So. 0.565 mol of Mg reacts completely with (0.2825 mol) of O₂.

<em>∴ The limiting reactant is O₂, and the excess reactant is Mg (0.6708 - 0.565 = 0.1058 mol).</em>

<u><em>Using cross multiplication:</em></u>

1.0 mole of Mg produce → 1.0 mol of MgO.

∴ 0.565 mol of Mg produce → <em>0.565 mol of MgO.</em>

<em>∴ The amount of MgO produced = no. of moles x molar mass </em>= (0.565 mol)(40.3 g/mol) = <em>22.77 g.</em>

8 0
3 years ago
Read 2 more answers
What type of chemical reaction is AgNO3(aq)+KCL(aq) AgCL(s)+KNO3(aq)​
emmasim [6.3K]

Answer:

double replacement reaction or double displacement reaction,

Explanation:

double replacement reaction, double displacement reaction, is a chemical process involving the exchange of bonds between two non-reacting chemical species which results in the creation of products with similar or identical bonding affiliations

Classically, these reactions result in the precipitation of one product.

in thía case it is AgCl

3 0
4 years ago
Consider the following reaction between mercury(II) chloride and oxalate ion.
natali 33 [55]

Answer:

a) rate law =  k[HgCl₂][C₂O₄²⁻]²

b) K = 8.67 * 10⁻⁵M⁻²s⁻¹

c) rate = 2.55 * 10⁻⁵Ms⁻¹

Explanation:

a) From the given data, rate law is given as: rate = k[HgCl₂]ᵃ[C₂O₄²⁻]ᵇ

Note: Further calculations and explanations are found in the attachment below

6 0
3 years ago
A quantity of 0.0250 mol of a gas initially at 0.050 L and 19.0°C undergoes a constant-temperature expansion against a constant
KiRa [710]

Answer:

V_2=2.995L\\\\W=248.5J

Explanation:

Hello,

In this case, for us to compute the final volume we apply the Boyle's law that analyzes the pressure-volume temperature as an inversely proportional relationship:

P_1V_1=P_2V_2

So we solve for V_2 by firstly computing the initial pressure:

P_1=\frac{nRT}{V_1}=\frac{0.025mol*0.082\frac{atm*L}{mol*K}*(19+273.15)K}{0.050L}  =11.98atm

V_2=\frac{P_1V_1}{P_2}=\frac{11.98atm*0.050L}{0.200atm}\\ \\V_2=2.995L

Finally, we can compute the work by using the following formula:

W=nRTln(\frac{V_2}{V_1} )=0.025mol*8.314\frac{J}{mol*K}*(19.0+273.15)K*ln(\frac{2.995L}{0.050L}) \\\\W=248.5J

Best regards.

4 0
4 years ago
Ming has two unknown substances. One is nonpolar, and the other is polar.
Verdich [7]
Hello
We know that polar molecules' attraction is stronger than that of non polar ones; this can be a good basis for us to check the substances' polarity. Knowing that polar forces are stronger, we can eliminate all options referring to them as being the weaker force; that is, options C and A. Next, we know that stronger forces will result in lower volatility so we can eliminate option D. The answer is B, assuming the compound has an odor.
3 0
3 years ago
Read 2 more answers
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