Answer:
22.77 g.
he limiting reactant is O₂, and the excess reactant is Mg.
Explanation:
- From the balanced reaction:
<em>Mg + 1/2O₂ → MgO,</em>
1.0 mole of Mg reacts with 0.5 mole of oxygen to produce 1.0 mole of MgO.
- We need to calculate the no. of moles of (16.3 g) of Mg and (4.52 g) of oxygen:
no. of moles of Mg = mass/molar mass = (16.3 g)/(24.3 g/mol) = 0.6708 mol.
no. of moles of O₂ = mass/molar mass = (4.52 g)/(16.0 g/mol) = 0.2825 mol.
So. 0.565 mol of Mg reacts completely with (0.2825 mol) of O₂.
<em>∴ The limiting reactant is O₂, and the excess reactant is Mg (0.6708 - 0.565 = 0.1058 mol).</em>
<u><em>Using cross multiplication:</em></u>
1.0 mole of Mg produce → 1.0 mol of MgO.
∴ 0.565 mol of Mg produce → <em>0.565 mol of MgO.</em>
<em>∴ The amount of MgO produced = no. of moles x molar mass </em>= (0.565 mol)(40.3 g/mol) = <em>22.77 g.</em>
Answer:
double replacement reaction or double displacement reaction,
Explanation:
double replacement reaction, double displacement reaction, is a chemical process involving the exchange of bonds between two non-reacting chemical species which results in the creation of products with similar or identical bonding affiliations
Classically, these reactions result in the precipitation of one product.
in thía case it is AgCl
Answer:
a) rate law = k[HgCl₂][C₂O₄²⁻]²
b) K = 8.67 * 10⁻⁵M⁻²s⁻¹
c) rate = 2.55 * 10⁻⁵Ms⁻¹
Explanation:
a) From the given data, rate law is given as: rate = k[HgCl₂]ᵃ[C₂O₄²⁻]ᵇ
Note: Further calculations and explanations are found in the attachment below
Answer:

Explanation:
Hello,
In this case, for us to compute the final volume we apply the Boyle's law that analyzes the pressure-volume temperature as an inversely proportional relationship:

So we solve for
by firstly computing the initial pressure:


Finally, we can compute the work by using the following formula:

Best regards.
Hello
We know that polar molecules' attraction is stronger than that of non polar ones; this can be a good basis for us to check the substances' polarity. Knowing that polar forces are stronger, we can eliminate all options referring to them as being the weaker force; that is, options C and A. Next, we know that stronger forces will result in lower volatility so we can eliminate option D. The answer is B, assuming the compound has an odor.