The escape velocity of the dwarf planet is 1,721.8 m/s.
The given parameters:
- <em>Mass of the dwarf planet, m = 0.0045 M</em>
- <em>Mass of the Earth = 5.98 x 10²⁴ kg</em>
- <em>Diameter of the planet, d = 0.19 D</em>
- <em>Diameter of the Earth, D = 12,742 km</em>
The mass of the of the dwarf planet is calculated as follows;
The radius of the dwarf planet is calculated as follows;
The escape velocity of the dwarf planet is calculated as follows;
Learn more about escape velocity here: brainly.com/question/13726115
If you were given distance & period of time, you would be able to calculate the speed.
Hope this helps!
Answer:
691 m
Explanation:
In these problems the time a ball is in the air is determined by the gravitational acceleration (y-coordinate) and the distance it travels is related to the velocity in the x-coordinate.
First get the x and y components of the initial speed.
Initial speed has a magnitude of 125 and a direction of 30°
speed in x = 125 cos 30° = 108.3 m/s
speed in y = 125 sin 30° = 62.5 m/s
The time it takes to the ball to reach the highest height (when the speed in the y-coordinate is 0) is:
0 = 62.5 - 9.8*t
t = 6.38 s
With the time you can calculate the distance travelled in the x-coordinate at a constant speed of 108.3.
d = vt
d = 108.3 * 6.38
d = 691 m
It is called an "orbit". Repeating and regular path that one object in space takes around in another one. This object ca be satellite or natural satellite like our moon. Planets, comets, asteroids and other objects in the solar system orbit the sun. Orbits come in different forms or shapes. All orbit are elliptical which means they are ellipse, similar to oval.
<span>Quantitative. I hopes this helps you some!</span>