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Anton [14]
3 years ago
14

Elemental calcium reacts with water at room temperature to form calcium hydroxide and hydrogen gas as shown in this equation. So

dium undergoes a similar reaction with H2O. What would be the coefficient for sodium in a similar reaction?
Chemistry
2 answers:
dem82 [27]3 years ago
8 0
Reaction of Elemental Calcium with Water is as follow,

                        Ca  +  2 H₂O    →    Ca(OH)₂  +  H₂↑

When Sodium Metal is reacted with Water it produces NaOH and eliminates Hydrogen gas as shown in following equation,

                         2 Na  +  2 H₂O    →    2 NaOH  +  H₂↑

In both cases corresponding Hydroxides along with Hydrogen gas is produced.
Iteru [2.4K]3 years ago
4 0

The answer is 2

hope this helps

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Heat moves from what source by convection and radiation?
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heat can move from any source but if we are being legitimate it moves from convection

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Butane, C4H10, reacts with oxygen, O2, to form water, H2O, and carbon dioxide, CO2, as shown in the following chemical equation:
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The balanced chemical reaction is:

<span>2C4H10(g)+13O2(g)->10H2O(g)+8CO2(g) 
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<span>Calculate the mass of water produced when 1.77 grams of butane reacts with excessive oxygen?
</span>1.77 g C4H10 (1 mol C4H10/58.14 g C4H10) (10 mol H2O / 2 mol C4H10) ( 1.01 g H2O / 1 mol H2O ) = <span>0.15 g H2O

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4 0
3 years ago
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Help please I’ll give you brainless
Helen [10]
• Liquid at room temperature
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Black_prince [1.1K]

Answer:

\large \boxed{\text{41.2 cm}^{3}}

Explanation:

1. Mass of zinc

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D = m/V

\begin{array}{rcl}7.14 & = & \dfrac{m}{15.0}\\\\m & = & 7.14 \times 15.0\\& = & \text{107.1 g}\\\end{array}\\

2. Volume of aluminium

The density of aluminium is 2.60/cm³.

\begin{array}{rcl}2.60 & = & \dfrac{107.1}{V}\\\\2.60V & = & 107.1\\V& = &\dfrac{107.1}{2.60}\\\\& = &\textbf{41.2cm}^{\mathbf{3}}\\\end{array}\\\large \boxed{\textbf{41.2 cm}^{\mathbf{3}}}\text{ of aluminium have the same mass as 15.0 cm$^{3}$ of zinc.}

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4 years ago
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A gas has more free molecules, and it is air, not a tangible substance. Hope it helps! :)
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