Answer : The volume for 6.0m HCl solution required = 62.5 ml
Solution : Given,
Initial concentration of HCl solution = 6.0m
Final concentration of HCl solution = 1.5m
Final volume of HCl solution = 250 ml
Initial volume of HCl solution = ?
Formula used for dilution is,
where,
= initial concentration
= final concentration
= initial volume
= final volume
Now put all the given values in above formula, we get the initial volume of HCl solution.
= 62.5 ml
Therefore, the volume for 6.0m HCl solution required = 62.5 ml
Considering the reaction:
3NO₂ + H₂O → 2HNO₃ + NO
To produce 3.56 moles of nitric acid, we require:
3.56 x 3/2 moles of NO₂
Moles of NO₂ = 5.34 moles of NO₂
Answer:
Mass = 132 g
Explanation:
Given data:
Mass of CO₂ formed = ?
Mass of C burnt = 36 g
Solution:
Chemical equation:
C + O₂ → CO₂
Number of moles of carbon:
Number of moles = mass/molar mass
Number of moles = 36 g/ 12 g/mol
Number of moles = 3 mol
now we will compare the moles of carbon and carbon dioxide.
C : CO₂
1 : 1
3 : 3
Mass of CO₂:
Mass = number of moles × molar mass
Mass = 3 mol × 44 g/mol
Mass = 132 g
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