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zzz [600]
3 years ago
5

Explain why you agree or disagree with this statement

Chemistry
1 answer:
defon3 years ago
4 0
Friction actually generated friction because you create charges that are dealing with electricity. When you rub some against each other , you can create a little spark which is electricity . Friction can produce static or something because it can be transferred by two or more items .
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Methane can be decomposed into two simpler substances: hydrogen and carbon. Therefore, methane 1. is a gas. 2. cannot be an elem
Reika [66]

Answer: 2. cannot be an element.

Explanation:

Element is a pure substance which is composed of atoms of similar elements.It can not be decomposed into simpler constituents using chemical reactions.Example: Copper Cu

Compound is a pure substance which is made from atoms of different elements combined together in a fixed ratio by mass.It can be decomposed into simpler constituents using chemical reactions. Example: methane CH_4

CH_4\rightarrow C+2H_2

Thus as it can be decomposed into its constituent elements, it is a compound.

Mixture is a substance which has two or more components which do not combine chemically and do not have any fixed ratio in which they are present.

Thus methane cannot be an element.

3 0
3 years ago
The properties of a substance are not affected by chemical reactions.<br> O True<br> O False
ElenaW [278]

Answer:

False

Explanation:

3 0
2 years ago
Someone please help me with this ???
Verizon [17]

Answer:

c

Explanation:

6 0
3 years ago
Is oil and water a solution, colloid, or suspension?
Ulleksa [173]
Emulsions are an example of colloids<span> composed of tiny particles </span>suspended<span> in another immiscible (unmixable) material. An emulsion is a </span>suspension<span> of two liquids that usually do not mix together. These liquids that do not mix are said to be immiscible. An example would be </span>oil and water<span>.
INFORMATION HOPE THIS HELPED! PLEASE MARK ME AS BRAINLIEST THANK YOU.

</span>
7 0
3 years ago
1. Express in conventional notation (no exponents) in the space provided within the
mina [271]

Answer:

a) 320: two significant figures.

b) 2,366: four significant figures.

c) 73.0: three significant figures.

d. 532.5: four significant figures.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to write each number by knowing we move the decimal places to the right as much as the exponent is, and also, we count every figure, even zeros, because they are to the right of the first nonzero digit:

a) 320: two significant figures because the rightmost zero is not preceded o followed by a decimal place.

b) 2,366: four significant figures.

c) 73.0: three significant figures, because the zero is followed by the decimal place.

d. 532.5: four significant figures.

Regards!

7 0
3 years ago
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