Answer:
m = 4.7 μg
Explanation:
Given data:
density of acetone = 60.0 μg/L
Volume = 79.0 mL
Mass = ?
Solution:
Formula:
d = m/v
v = 79.0 mL × 1L /1000 mL
v = 0.079 L
Now we will put the values on formula:
d = m/v
60.0 μg/L = m/0.079 L
m = 60.0 μg/L × 0.079 L
m = 4.7 μg
So health risk limit for acetone = 4.7 μg
Answer:
3.46 g of BaCl2
Explanation:
The equation of the reaction is;
BaCl2(aq) + Na2SO4(aq) --------> 2NaCl(aq) + BaSO4(s)
Number of moles of barium sulphate produced = 3.88 g/233.38 g/mol = 0.0166 moles
From the reaction equation;
1 mole of BaCl2 yields 1 mole of barium sulphate
Hence 0.0166 moles of BaCl2 yields 0.0166 moles of barium sulphate
Hence;
Mass of BaCl2 required = 0.0166 moles × 208.23 g/mol = 3.46 g of BaCl2
Answer:
The answer is larynx. I believe it is anyways. Sorry if i'm wrong.
It's being dissolved so it's the solute
Answer :
The atmospheric pressure of water if boiling at 81 °C will be 369 mmHg.
Explanation : The vapor pressure of boiling water can be calculated using the Antoine Equation:
log P = A - ,
where P is the pressure in mmHg,
A = 8.07131,
B = 1730.63
C = 233.426
and T = temperature in °C (81°C)
Substituting the given values, we get,
Log P = 8.07131−
Therefore, Log P =8.07131 − 5.5041 = 2.567.
Now, P = =369 mmHg.
Hence, the atmospheric pressure will be 369 mmHg.