3) What is the mass of a sample consisting of 1.00 X 1022 formula units of MgSO.?(

Chemistry

1 answer:

Montano1993 [528]2 years ago

4 0

number of moles = 1.00 X 10^22 ÷ 6.022 × 10^23

= 0.0166 moles

mass = number of moles × molar mass

= 0.0166 × 120.37 = 2.00 g

You might be interested in

Iron has a density of 7.9 space straight g divided by cm cubed. How much mass is in a 10 space cm cubed sample of iron? Question

dezoksy [38]

Answer:

79 g

Explanation:

Density (d) of iron = 7.9 g/cm³

Volume of the iron (V) = 10 cm³

Mass of the iron (m) = ?

Solution:

Formula will be used

d = m/V

As we have to find mass so rearrange the above equation

m = dV . . . . . . . . . . . (1)

Put values in above equation 1

m = 7.9 g/cm³ x 10cm³

m = 79 g

So,

mass of iron = 79 g

6 0

3 years ago

. Metallic iron has a body-centered cubic lattice with all atoms at lattice points and a unit cell whose edge length is 286.6 pm

adell [148]

Answer:

$\large \boxed{\text{55.8 u}}$

Explanation:

1. Calculate the volume of the unit cell

V = l³ = (2.866 × 10⁻⁸ cm)³ = 2.354 × 10⁻²³ cm³

2. Calculate the mass of a unit cell

$\text{Mass} = 2.866 \times 10^{-23}\text{ cm}^{3} \times \dfrac{\text{7.87 g}}{\text{1 cm}^{3}} = 1.853 \times 10^{-22} \text{ g}$

3. Calculate the mass of one atom

A body-centred unit cell contains two atoms.

$\text{Mass of 1 atom} = \dfrac{1.853 \times 10^{-22} \text{ g}}{\text{2 atoms}} \times \dfrac{\text{1 u}}{1.661 \times 10^{-24}\text{ g}} = \textbf{55.8 u}\\\\\text{The molar mass of Fe from the Periodic Table is $\large \boxed{\textbf{55.845 g/mol}}$}$