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weeeeeb [17]
3 years ago
8

Calculate the molarity of a solution of potassium hydroxide if 19.55 mL of KOH is required for the titration of a 20.20 mL sampl

e of a 0.3467 M sulfuric acid solution.
Chemistry
1 answer:
VMariaS [17]3 years ago
5 0

Answer:

The correct answer is 0.3582 M.

Explanation:

Based on the given information, the volume of KOH given is 19.55 ml, the volume of sulfuric acid given is 20.20 ml, and the molarity of sulfuric acid is 0.3467 M. There is a need to find the molarity of KOH.

The formula to use in the given case is,

M1V1 = M2V2

Here M1 is the molarity of KOH, V1 is the volume of KOH, M2 is the molarity of sulfuric acid, and V2 is the volume of H2SO4.

Here V1 is 19.55 ml, M2 is 0.3467 M, and V2 is 2020 ml.

Now putting the values in the equation we get,

M1 * 19.55 = 0.3467 * 20.20

M1 * 19.55 = 7.00334

M1 = 7.00334/19.55

M1 = 0.3582 M

Hence, the molarity of the given KOH is 0.3582.

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Answer:

When the hammer is in the sun, heat flows by radiation

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Explanation:

As the hammer lies in the sun, heat is transferred to the hammer by radiation. Heat energy reaches the earth from the sun by radiation. Radiation is a mode of beat transfer in which heat is transferred without a material medium.

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3 years ago
How many bromine atoms are present in 39.4 g of CH2Br2
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37.8 g CH2Br2 X (1 mol CH2Br2 / 173.83 g) = 4.60X10^-3 mol CH2Br2 

<span>4.60X10^-3 mol CH2Br2 X (2 mol Br / 1 mol CH2Br2) X 6.02X10^23 atoms/mol = 5.54X10^21 bromine atoms</span>
7 0
4 years ago
The molar mass of an unknown gas was measured by an effusion experiment. It was found that it took 60 s for the gas to effuse, w
Marizza181 [45]

Answer:

The molar mass of the gas is 44 g/mol

Explanation:

It is possible to solve this problem using Graham's law that says: Rates of effusion are inversely dependent on the square of the mass of each gas. That is:

\frac{r_1}{r_2} =\frac{\sqrt{M_2} }{\sqrt{M_1} }

If rate of effusion of nitrogen is Xdistance / 48s and for the unknown gas is X distance / 60s and mass of nitrogen gas is 28g/mol (N₂):

\frac{X/48s}{X/60s} =\frac{\sqrt{M_2} }{\sqrt{28g/mol} }

6,61 = √M₂

44g/mol = M₂

<em>The molar mass of the gas is 44 g/mol</em>

<em></em>

I hope it helps!

4 0
3 years ago
Several constructive processes helped build mountains on Earth. All BUT one of these is a way mountains can be built. That is A)
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4 years ago
Identify each of the following mixtures as either homogeneous or heterogeneous and as a solution, a suspension, or a colloid.
MrRissso [65]
<h2>Answers to the rest of the assignment:</h2>

**Check for proof photos at the bottom.**

__________________________________________________________

Identify each of the following mixtures as either homogeneous or heterogeneous and as a solution, a suspension, or a colloid.  

Cranberry juice at the store

A. homogeneous

C. solution

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B. heterogeneous  

D. colloid

__________________________________________________________

Identify each of the following mixtures as either homogeneous or heterogeneous and as a solution, a suspension, or a colloid.  

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B. heterogeneous  

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__________________________________________________________

Shown here is a person shaving.  Under magnification, the shaving foam might look like the image above the shaver. What type of mixture does the foam demonstrate? Give your reasoning.

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On the next slide, you can select any answers you want, or you can select nothing. There's no wrong answer.  

__________________________________________________________

A student squeezes several oranges to make a glass of orange juice. The juice contains pieces of orange pulp mixed with the juice. Explain why this drink can be considered a combination of a suspension and a solution.

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On the right side, you can also select any answers or none at all. There is no wrong answer.

__________________________________________________________

<h2>Explanation:</h2>

There are two main types of mixtures, homogeneous mixtures and heterogeneous mixtures. The components of a homogeneous mixture are evenly distributed throughout the mixture. The properties of a mixture are the same everywhere. The components of a heterogeneous mixture are not evenly distributed. Different regions of this mixture have different   properties.

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Here are photos of Edge just incase.

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