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atroni [7]
3 years ago
10

Which statement is not correct for lamps connected in parallel

Physics
1 answer:
ycow [4]3 years ago
6 0

Answer:

This question is not complete but the completed question is below

Which statement is not correct for lamps connected in parallel?

A They can be switched on and off separately.

B They will remain bright if another lamp is connected in parallel.

C They share the supply voltage equally between them.

D They still operate if one lamp is removed.

The correct option is A

Explanation:

Lamps connected in series have the same voltage running across each lamp in the connection and will thus have the same brightness if any lamp is added or removed. This property also means they can only be switched on and off by a single switch, hence option A is not correct about lamps connected in parallel.

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Suppose A = B"Cm, where A has the dimensions LT, B has dimensions L²T-1, and C has dimensions LT2. Then the exponents n and have
tresset_1 [31]

Complete Question:

Suppose A = B^n C^m, where A has the dimensions LT, B has dimensions L²T⁻¹, and C has dimensions LT². Then the exponents n and m have the values

Answer:

The value of n = ¹/₅

The value of m = ³/₅

Explanation:

Given dimensions;

A = LT

B = L²T⁻¹

C = LT²

The values of n and m are calculated as follows;

LT = [L^2T^{-1}]^n[LT^2]^m\\\\L^1T^1 = [L^{2n}T^{-n}]\times [L^mT^{2m}]\\\\L^1 \times T^1 = [L^{(2n+m)}] \times [T^{(-n +2m)}]\\\\1 = 2n + m -----(1)\\\\1 = -n + 2m ----(2)\\\\from  \ (1); \ m = 1-2n, \ \ substitute \ the \ value \ of \ m \ in\  (2)\\\\1= -n +2(1-2n)\\\\1 = -n + 2-4n\\\\1-2 = -5n\\\\-1 = -5n\\\\1= 5n\\\\n = \frac{1}{5} \\\\m = 1 - 2n\\\\m = 1 - 2(\frac{1}{5} )\\\\m = 1- \frac{2}{5} \\\\m = \frac{3}{5}

8 0
3 years ago
Please help me<br><br><br><br><br> Why do objects in the sky appear to move and change so much?
bearhunter [10]

Answer:

It depends on the climate and wind speed at the time.

If the climate is hot and no breeze it will move slower.

If it is cold and very windy it will move rapidly.

6 0
3 years ago
What type of contraction requires the greatest amount of tension?
mars1129 [50]

Answer:

Isotonic eccentric

Explanation:

First of all, it should be noted that the term contraction has the meaning of joining or shortening. In the field of bodybuilding and workouts with loads, we can define muscle contraction as what happens whenever muscle fibers generate a tension in themselves.

This tension situation occurs in several situations, including when the muscle is shortened, elongated, moving, maintaining the same length or static.

There are different types of muscle contraction, among them we can highlight isotonic contraction, which is divided in turn into concentric and eccentric, isometric, auxotonic and isokinetic contraction.

 Isotonic contraction is the most common type of contraction that occurs in most sports or physical activities that we perform in our day to day. Normally the muscular tensions that we exert are usually accompanied by a shortening and lengthening of the muscle fibers of a muscle. In turn, the isotonic contraction is divided into two, concentric and eccentric.

Concentric concentration: is that which happens when a muscle makes a tension capable of overcoming a resistance, producing a shortening and subsequent mobilization of a part of the body overcoming said resistance. For example, when we take a spoon and take it to our mouths to eat, a concentric shortening occurs. Putting examples in the gym on the bench press the movement of raising the bar, is equivalent to the concentric phase.

Eccentric concentration: we can say that it is one in which, given a resistance, we exert a greater tension with the muscle, so that said muscle is lengthened. In the case of the bench press, the eccentric phase is when we lower the bar to the chest.

8 0
3 years ago
Ask Your Teacher Cam Newton of the Carolina Panthers throws a perfect football spiral at 6.9 rev/s. The radius of a pro football
faltersainse [42]

Answer:

a=159.32\ m/s^2

Explanation:

It is given that,

Angular speed of the football spiral, \omega=6.9\ rev/s=43.35\ rad/s

Radius of a pro football, r = 8.5 cm = 0.085 m

The velocity is given by :

v=r\omega

v=0.085\times 43.35

v = 3.68 m/s

The centripetal acceleration is given by :

a=\dfrac{v^2}{r}

a=\dfrac{(3.68)^2}{0.085}

a=159.32\ m/s^2

So, the centripetal acceleration of the laces on the football is 159.32\ m/s^2. Hence, this is the required solution.

6 0
3 years ago
[O.04H]The table below shows the use of some energy production methods over time.
mr Goodwill [35]

I think The coastal areas were highly polluted

8 0
3 years ago
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