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Papessa [141]
3 years ago
14

Match the atoms to their correct electron configuration. (Answer choices in photo)

Chemistry
1 answer:
zysi [14]3 years ago
6 0

Answer:

The answer to your questions are given below

Explanation:

The answer to the questions given above can simply be obtained by writing the electronic configuration of each atom.

The electronic configuration of each atoms can be written as follow:

Fluorine, F (9) => 1s² 2s²2p⁵

Sodium, Na (11) => [Ne] 3s¹

Helium, He (2) => 1s²

Calcium, Ca (20) => [Ar] s²

Nitrogen, N (7) => 1s² 2s²2p³

Sulphur, S (16) => [Ne] 3s²3p⁴

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5 0
2 years ago
Which of the following chemical formulas show three molecules of a compound that has one
mr_godi [17]

The chemical formula : 3HgBr₂(Mercury(II) bromide)

<h3>Further explanation</h3>

Given

The chemical formulas of Mercury and Bromine

Required

The appropriate chemical formula

Solution

A molecular formula is a formula that shows the number of atomic elements that make up a compound.  

The number of molecules is determined by the coefficient in front of the compound

the number of atoms is determined by the subscript after the atom and the coefficient

Three molecules⇒ coefficient = 3

one atom of Mercury ⇒Hg

two atoms of Bromine ⇒ Br₂

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2 years ago
What does Newton's first law of motion state ​
Alenkasestr [34]

Answer:

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Explanation:

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8 0
2 years ago
Calculate the density of sulfuric acid if 35.4 mL of the acid weighs 65.14 g
Nadya [2.5K]
M/V=D
65.14/35.4≈1.84
The density of the sulfuric acid would be about 1.84g/mL
5 0
2 years ago
3. In an experiment it was found that 40.0cm of 0.2M sodium hydroxide solution just neutralized 0.2g
hjlf

The relative molecular mass of acid A : 50 g/mol

<h3>Further explanation</h3>

Given

40.0 cm³(40 ml) of 0.2M sodium hydroxide

0.2g  of a dibasic acid

Required

the relative molecular mass of acid A

Solution

Titration formula

M₁V₁n₁=M₂V₂n₂

n=acid/base valence(number of H⁺/OH⁻)

NaOH ⇒ n = 1

Dibasic acid =  diprotic acid (such as H₂SO₄)⇒ n = 2

mol = M x V

Input the value in the formula :(1 = NaOH, 2=dibasic acid)

0.2 x 40 x 1 = M₂ x V₂ x 2

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The relative molecular mass of acid A (M) :

\tt M_A=\dfrac{mass }{mol}=\dfrac{0.2~g}{4.10^{-3}}=50~g/mol

5 0
3 years ago
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