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Alenkinab [10]
3 years ago
9

HELPPPP!!!!!!!!!!!!

Chemistry
1 answer:
xenn [34]3 years ago
3 0

Answer:

nomelase ay pa la próxima

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A materials scientist has created an alloy containing aluminum, copper, and zinc, and wants to determine the percent composition
liubo4ka [24]

Answer:

0.8749 grams of hydrogen gas was formed from the reaction.

Explanation:

P = Pressure of hydrogen gad= 744 Torr = 0.98 atm

(1 atm = 760 Torr)

V = Volume of hydrogen gas= 11 L

n = number of moles of hydrogen gas= ?

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of vapor = 27.0 °C = 300.15 K

Putting values in above equation, we get:

Using an ideal gas equation:

PV=nRT

n=\frac{PV}{RT}=\frac{0.98 atm\times 11 L}{0.0821 L atm/mol K\times 300.15 K}

n = 0.4374 moles

Mass of 0.4374 moles of hydrogen gas:

0.4374 mol × 2 g/mol = 0.8749 g

0.8749 grams of hydrogen gas was formed from the reaction.

7 0
3 years ago
An organic compound that contains a carbonyl group with a hydroxyl group attached to it is an example of a(n)
lawyer [7]
An organic compound that contains a carbonyl group with a hydroxyl group attached to it is an example of a (d) carboxylic acid.
8 0
3 years ago
The chemical formula for sulfuric acid is H2SO4. In one molecule of sulfuric acid, there are _____.
erma4kov [3.2K]

Answer:

four atoms of oxygen

Explanation:

two atoms of hydrogen

one sulphur atom

5 0
3 years ago
Read 2 more answers
Calculate the molality of 75.0 grams of MgCl2 (molar mass=95.21 g/mol) dissolved in 500.0 g of solvent.
nordsb [41]

<u>Answer:</u> The molality of magnesium chloride is 1.58 m

<u>Explanation:</u>

To calculate the molality of solution, we use the equation:

\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

Where,

m_{solute} = Given mass of solute (magnesium chloride) = 75.0

M_{solute} = Molar mass of solute (magnesium chloride) = 95.21 g/mol  

W_{solvent} = Mass of solvent = 500.0 g

Putting values in above equation, we get:

\text{Molality of }MgCl_2=\frac{75.0\times 1000}{95.21\times 500.0}\\\\\text{Molality of }MgCl_2=1.58m

Hence, the molality of magnesium chloride is 1.58 m

5 0
4 years ago
Read 2 more answers
Can someone please help me please?
OleMash [197]
I would say the second option

Hope this helps *smiles*
8 0
3 years ago
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