2 years ago

Can someone please help me please?

Chemistry

1 answer:

OleMash [197]2 years ago

8 0

I would say the second option

Hope this helps *smiles*

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D-1 electron in their outer energy level.

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2 years ago

Compound B, C6H12O2, was found to be optically active, and it was oxidized to an optically active carboxylic acid A, by Ag (aka,

Daniel [21]

Answer:

Check the explanation

Explanation:

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Kindly check the attached image below for the full explanation to the question above.

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2 years ago

Sodium-25 was to be used in an experiment, but it took 3.0 minutes to get the sodium from the reactor to the laboratory. If 8.0

Ksenya-84 [330]

Sodium-25 after 3 minutes : 1.0625 mg

<h3>Further explanation</h3>

General formulas used in decay:

$\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}$

T = duration of decay

t 1/2 = half-life

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Nt = the number of radioactive atoms left after decaying during T time

<h3 />

No=8 mg

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$\tt Nt=No\dfrac{1}{2}^{T/t1/2}\\\\Nt=8.5\dfrac{1}{2}^{180/60}\\\\Nt=8.5(\dfrac{1}{2})^3\\\\Nt=1.0625~mg$

5 0

2 years ago

Review the equation below. 2KClO3 mc012-1.jpg 2KCl + 3O2 How many moles of oxygen are produced when 2 mol of potassium chlorate

Vlada [557]

Stoichiometry <span>of the reaction:

</span><span>2 KClO</span>₃<span>   =   2 KCl + 3 O</span>₂
  ↓ ↓

2 mole KClO₃ ----------> 3 mole O₂
2 mole KClO₃ ----------> ?

KClO₃ = 2 * 3 / 2

KClO₃ = 6 / 2

= 3 moles de KClO₃

hope this helps!

4 0

3 years ago

Read 2 more answers