1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sati [7]
2 years ago
9

Why might exposing astronauts to weightlessness be harmful?

Physics
1 answer:
love history [14]2 years ago
5 0
The body doesn't have to work as hard when there's no gravity for it to work against, so it becomes accustomed to a much lower work load on every level. It leads to lower bone mass and weaker muscles, including the heart, leading to a drop in blood pressure that can eventually build up to create problems with cognitive function. After so long, minor accidents can lead to major, even life threatening problems. A simple bump that would do little more than leave a bruise on you and I can result in a broken femur bone or broken neck on an astronaut who has been exposed to a weightless environment for too long.

This is one of the several hurdles that must be overcome in order for a manned mission to Mars to succeed. Exposure to a weightless environment on the order of roughly two years for a manned Mars mission would be so degrading to the body that the rough, turbulent re-entry into Earth's atmosphere might prove to be too violent for an astronaut to survive.

The problem is bones.

On Earth, every time you do something with "impact" (like walking), there are microcracks in your bones. Calcium is used by the body to fix these cracks... and that is how the bones grow and become strong.

No weight = no impact = no cracks = no "repairs" being done by the body = the body gets rid of un-neede calcium and bones become brittle and weak.

There are some other operations in the body that require gravity as a "director", or resistance to movement as a driver of change (think of muscles in the legs, when there is no need to walk).

The organ themelves are (generally) OK since many things can work in any orientation.
You might be interested in
2). If you record a wave going 4m/s and the Period of the wave was<br> 60s, how long was the wave?
Taya2010 [7]

Answer:240 meters

Explanation:60×4

8 0
3 years ago
A quantum system has three states, with energies 0, 1.6 × 10-21, and 1.6 × 10-21, in Joules. It is coupled to an environment wit
xenn [34]

To develop the problem it is necessary to apply two concepts, the first is related to the calculation of average data and the second is the Boltzmann distribution.

Boltzmann distribution is a probability distribution or probability measure that gives the probability that a system will be in a certain state as a function of that state's energy and the temperature of the system. It is given by

z = \sum\limit_i e^{-\frac{\epsilon_i}{K_0T}}

Where,

\epsilon_i = energy of that state

k = Boltzmann's constant

T = Temperature

With our values we have that

T= 250K

k = 1.381*10^{23} m^2 kg s^{-2} K^{-1}

\epsilon_1=0J

\epsilon_2=1.6*10^{-21}J

\epsilon_3=1.6*10^{-21}J

To make the calculations easier we can assume that the temperature and Boltzmann constant can be summarized as

\beta = \frac{1}{kT}

\beta = \frac{1}{(1.381*10^{23} m^2)(250)}

\beta = 2.9*10^{20}J

Therefore the average energy would be,

\bar{\epsilon} =\frac{\sum \epsilon_i e^{-\beta \epsilon_i}}{\sum e^{-\beta \epsilon_i}}

Replacing with our values we have

\bar{\epsilon} = \frac{0e^{-0}+1.6*10^{-21}*e^{-\Beta(1.6*10^{-21})}+1.6*10^{-2-1}*e^{-(2.9*10^{20})(1.6*10^{-21})}}{1+2e^{-2.9*10^{20}*1.6*10^{-21}}}

\bar{\epsilon} = 0.9*10^{-22}J

Therefore the average internal energy is \bar{\epsilon} = 0.9*10^{-22}J

3 0
3 years ago
3.5 g of a hydrocarbon fuel is burned in a vessel that contains 250. grams of water initially at 25.00 C. After the combustion,
kherson [118]

Answer:

3.) 463 J/g

Explanation:

Heat given by the fuel is used to increase the temperature of the water

so it is given as

Q = ms\Delta T

here we will have

m = 250 g

\Delta T = 26.55 - 25

now we also know that

s = 4186

so we have

Q = (0.250)(4186)(26.55 - 25)

Q = 1622.075 J

so 3.5 g fuel gives above energy

so per gram of fuel will have total energy given as

Q = \frac{1622.075}{3.5}

Q = 463.45 J/g

6 0
3 years ago
Convert the following to gram. a,250 kg b373 mg c,10 quanital,15 ton​
rusak2 [61]

Explanation:

250 KG = 250000 Grams

373 MG = 0.373 Grams

10 Quintals = 1000000 Grams

15 Ton = 15000000 Grams

Please Follow and inbox me

4 0
2 years ago
Where does fusion regularly occur and what kind of energy is produced
AlexFokin [52]
Sun is the place where fusion continuously occurs.. heat energy is produce plus raditions are by product <span />
4 0
3 years ago
Read 2 more answers
Other questions:
  • What were the models of ancient greek atoms ?
    13·1 answer
  • A force of 15 N acts upon a 3 kg block. Calculate the acceleration of the object.
    12·1 answer
  • Light incident on a polarizer is then passed through a second polarizer. If the polarizer and the analyzer are perpendicular to
    9·2 answers
  • What is the self-inductance of a solenoid 30.0 cm long having 100 turns of wire and a cross-sectional area of 1.00 × 10-4 m2? (μ
    11·1 answer
  • Assume your car reaches a speed of 21.7 m/s at a steady rate for 5.05 s after the light turns green. (a) What distance have you
    12·1 answer
  • Part AIf the potential of plate 1 is V, then, in equilibrium, what are the potentials of plates 3 and 6? Assume that the negativ
    13·1 answer
  • An object with a mass of 30 kg moves at a rate of 15 m/S over distance of 10 m. 900 joules of work was done in 10 seconds. What
    14·1 answer
  • The potential difference across a piece of wire is 2.1 v the current in the wire is 0.30 a calculate the resistance of the wire
    7·1 answer
  • Where in space did the expansion of the universe begin?
    5·1 answer
  • How did Edwin Hubble's discovery that the Andromeda Nebula was at least 1 million light years away change scientists' view of th
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!