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Sati [7]
3 years ago
9

Why might exposing astronauts to weightlessness be harmful?

Physics
1 answer:
love history [14]3 years ago
5 0
The body doesn't have to work as hard when there's no gravity for it to work against, so it becomes accustomed to a much lower work load on every level. It leads to lower bone mass and weaker muscles, including the heart, leading to a drop in blood pressure that can eventually build up to create problems with cognitive function. After so long, minor accidents can lead to major, even life threatening problems. A simple bump that would do little more than leave a bruise on you and I can result in a broken femur bone or broken neck on an astronaut who has been exposed to a weightless environment for too long.

This is one of the several hurdles that must be overcome in order for a manned mission to Mars to succeed. Exposure to a weightless environment on the order of roughly two years for a manned Mars mission would be so degrading to the body that the rough, turbulent re-entry into Earth's atmosphere might prove to be too violent for an astronaut to survive.

The problem is bones.

On Earth, every time you do something with "impact" (like walking), there are microcracks in your bones. Calcium is used by the body to fix these cracks... and that is how the bones grow and become strong.

No weight = no impact = no cracks = no "repairs" being done by the body = the body gets rid of un-neede calcium and bones become brittle and weak.

There are some other operations in the body that require gravity as a "director", or resistance to movement as a driver of change (think of muscles in the legs, when there is no need to walk).

The organ themelves are (generally) OK since many things can work in any orientation.
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Desde que altura debes de lanzar una canica de 50g para que adquiera una energia de 100j
AnnZ [28]

Answer:

204 m

Explanation:

When the marble is dropped from a certain height, its gravitational potential energy converts into kinetic energy. So the kinetic energy gained is equal to the variation of gravitational potential energy:

\Delta U=mg\Delta h

where

m is the mass of the marble

g = 9.8 m/s^2 is the acceleration of gravity

\Delta h is the change in height

In this problem, we have

m = 50 g = 0.05 kg

\Delta U = 100 J

Solving the formula for \Delta h, we find the necessary height from which the marble should be dropped:

\Delta h = \frac{\Delta U}{mg}=\frac{100}{(0.05)(9.8)}=204 m

7 0
3 years ago
Express in words AND mathematically the relationship between…<br> Period and frequency
castortr0y [4]
Frequency = how many waves you get per sec
Period = how long each wave takes

Period = 1/frequency
6 0
3 years ago
The nuclear equation is incomplete. Superscript 239 Subscript 94 Baseline P u + Superscript 1 Subscript 0 Baseline n yields Supe
Crank

Answer:

The particle which completes the given equation  is :_{54}^{138}\textrm{Xe}

Explanation:

The given reaction is of a fission reaction:

_{94}^{239}\textrm{Pu}+_0^1\textrm{n}\rightarrow _{40}^{100}\textrm{Zr}+_Z^A\textrm{X}+2_0^1\textrm{n}

Total mass on the reactant side is equal to the total mass on the product side:

239 + 1 = 100 +A+ 2

A = 138

Sum of atomic numbers on the reactant side is equal to the sum of atomic number on the product side:

94 + 1(0) = 40 + Z + 2(0)

Z = 54

So atomic number 54 id of Xenon.

The particle which completes the given equation  is :

_{94}^{239}\textrm{Pu}+_0^1\textrm{n}\rightarrow _{40}^{100}\textrm{Zr}+_{54}^{138}\textrm{Xe}+2_0^1\textrm{n}

3 0
3 years ago
How does this level of organization relate to cells? To organ systems?
Setler [38]
System is a group of similar organs working together...... Organ is a group of similar tissues forming a layer in an organism which perform a specific function.....tissue is a group of similar cell which carry out a particular function
4 0
3 years ago
A person of mass m will bungee-jump from a bridge over a river where the height from the bridge to the river is h. The bungee co
Likurg_2 [28]

Answer:k_{min}=\frac{18mg}{h}

Explanation:

Given

mass of person is m

Distance between bridge and river is h

chord has an un-stretched length of \frac{2h}{3}

Let spring constant be k

Person will just stop before hitting the river

Conserve energy i.e. Potential Energy of Person is converted in to elastic energy of chord

mgh=\frac{kx^2}{2}

x=h-\frac{2h}{3}=\frac{h}{3}

mgh=\frac{kh^2}{18}

k=\frac{18mg}{h}

Thus k_{min}=\frac{18mg}{h}

5 0
3 years ago
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