Answer:
(A) L = 115.3kgm²/s
(B) dL/dt = 94.1kgm²/s²
Explanation:
The magnitude of the angular momentum of the rock is given by the foemula
L = mvrSinθ
We have been given θ = 36.9°, m = 2.0kg, v = 12.0m/s and r = 8.0m.
Therefore L = 2.00 × 12 × 8.0 × Sin 36.9° =
115.3 kgm²/s
(B) The magnitude of the rate of angular change in momentum is given by
dL /dt = d(mvrSinθ)/dt = mgrSinθ = 2.00 × 9.8 × 8.0× Sin36.9 = 94.1kgm²/s²
MULTIMETER combines the functions of ammeter, voltmeter and ohmmeter as a minimum.
Answer:
<em>the ball travels a distance of 8.84 m</em>
Explanation:
Range: Range is defined as the horizontal distance from the point of projection to the point where the projectile hits the projection plane again.
R = (U²sin2∅)/g.............................. Equation 1
Where R = range, U = initial velocity, ∅ = angle of projection, g = acceleration due to gravity.
<em>Given: U = 10 m/s, ∅ = 60°</em>
<em>Constant: g = 9.8 m/s²</em>
Substituting these values into equation 1
R = [10²×sin(2×60)]/9.8
R = (100sin120)/9.8
R = 100×0.8660/9.8
R = 86.60/9.8
R = 8.84 m
<em>Therefore the ball travels a distance of 8.84 m</em>
The ball in the air is for <u>0.319 sec.</u>
<u />
The horizontal pace of a projectile is regular (in no way converting in value), and there's a vertical acceleration because of gravity; its cost is 9.8 m/s/s, down, The vertical speed of a projectile changes via nine.8 m/s every second, The horizontal motion of a projectile is impartial to its vertical movement.
Projectile motion is a form of motion experienced with the aid of an object or particle that is projected in a gravitational field, such as from Earth's floor, and movements alongside a curved route below the action of gravity best.
Projectile motion is the movement of an object thrown (projected) into the air. After the initial force that launches the item, it most effectively reports the pressure of gravity. The object is known as a projectile, and its route is called its trajectory.
<u />
<u>Calculate:-</u>
<u />
H = ut + 1/2 gt²
Since the vertical initial velocity is 0.
H = 0 +gt²
t = 
= 
=<u> 0.319 sec.</u>
Learn more about projectile motion here:-brainly.com/question/10680035
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So when the body moves in a straight line the average velocity is equal to the average speed. average velocity would be equal to average speed when the total distance travelled equals the net displacement of a particle. this happens when a particle moves along a straight line in a fixed direction.
