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3 years ago

Determine the concentration of C5H5N that would produce a solution with a pH of 9.17.

Chemistry

1 answer:

Anna35 [415]3 years ago

8 0

Answer:

[C₅H₅N] = 1.34 X 10⁻⁵M

Explanation:

C₅H₅N(aq) having a pH of 9.17 would also have a pOH of 14 - 9.17 = 4.83.

Since Nitrogen derivatives form hydroxides in water then

C₅H₅N + H₂O => C₅H₅N:HOH => C₅H₆OH⁻ <=> C₅H₆⁺ + OH⁻

The [OH⁻] = 10⁻⁴.⁸³M = 1.348 x 10⁻⁵M

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Britney added 0.05 moles of copper(II) nitrate solution to 0.1 moles of sodium hydroxide solution and

Rama09 [41]

The percent yield of copper hydroxide is 84%

<h3>Stoichiometry</h3>

From the question, we are to determine the percent yield of copper hydroxide

First, we will determine the theoretical mass

From the given balanced chemical equation, we have

Cu(NO₃)₂ + 2NaOH -- Cu(OH)₂ + 2NaNO₃

This means,

1 mole of copper(II) nitrate reacts with 2 moles of sodium hydroxide to produce 1 mole of copper hydroxide

Therefore,
0.05 mole of copper(II) nitrate reacts with 0.1 mole of sodium hydroxide to produce 0.05 mole of copper hydroxide

The theoretical number of moles of copper hydroxide that is produced is 0.05 mole

Now, for the theoretical mass

Using the formula,

Mass = Number of moles × Molar mass

Molar mass of copper hydroxide = 97.56 g/mol

Then,

Theoretical mass = 0.05 × 97.56

Theoretical mass of copper of hydroxide produced is = 4.878 g

Now, for the percent yield of copper hydroxide

Percent yield is given by the formula,

$Percent\ yield = \frac{Actual\ yield}{Theoretical\ yield} \times 100\%$

Then,

$Percent\ yield\ of\ copper\ hydroxide= \frac{4.1}{4.878}\times 100\%$

$Percent\ yield\ of\ copper\ hydroxide= 84\%$

Hence, the percent yield of copper hydroxide is 84%.

Learn more on Stoichiometry here: brainly.com/question/9372758

7 0

3 years ago

How many grams N2F4 can be produced from 225 g F,?

zavuch27 [327]

Answer:

308 g

Explanation:

Data given:

mass of Fluorine (F₂) = 225 g

amount of N₂F₄ = ?

Solution:

First we look to the reaction in which Fluorine react with Nitrogen and make N₂F₄

Reaction:

2F₂ + N₂ -----------> N₂F₄

Now look at the reaction for mole ratio

2F₂ + N₂ -----------> N₂F₄

2 mole 1 mole

So it is 2:1 mole ratio of Fluorine to N₂F₄

As we Know

molar mass of F₂ = 2(19) = 38 g/mol

molar mass of N₂F₄ = 2(14) + 4(19) =

molar mass of N₂F₄ = 28 + 76 =104 g/mol

Now convert moles to gram

2F₂ + N₂ -----------> N₂F₄

2 mole (38 g/mol) 1 mole (104 g/mol)

76 g 104 g

So,

we come to know that 76 g of fluorine gives 104 g of N₂F₄ then how many grams of N₂F₄ will be produce by 225 grams of fluorine.

Apply unity formula

76 g of F₂ ≅ 104 g of N₂F₄

225 g of F₂ ≅ X of N₂F₄

Do cross multiplication

X of N₂F₄ = 104 g x 225 g / 76 g

X of N₂F₄ = 308 g

So,

308 g N₂F₄ can be produced from 225 g F₂

7 0

3 years ago

What are the properties of seismic waves?

natima [27]

Answer: incompressibility, rigidity, and density

Explanation:

6 0

2 years ago

The emission spectrum of hydrogen consists of several lines. Which line has the highest frequency?

solong [7]

Answer:

410 nm

Explanation:

The highest frequency is associated with the shortest wavelength. Of those listed, 410 nm is the shortest.

8 0

4 years ago

Although cotton and wool are natural fibers, their production uses large quantities of water and other resources. Synthetic mate

lorasvet [3.4K]

C I think..........................

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3 years ago