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Dafna11 [192]
3 years ago
9

Electromagnetic energy released during fusion is converted to other kinds of photons as it is transferred through which layer of

the Sun?
Chemistry
2 answers:
sertanlavr [38]3 years ago
4 0

Answer:

Radioactive zone

Explanation:

I did a quiz and got it right.

Yuri [45]3 years ago
3 0
Electromagnetic energy released during fusion is converted to other kinds of photons as it is transferred through the RADIATIVE layer of the sun. The sun is divided into five distinct layers, which are: the core, the radiative zone, the convective zone, the photosphere and the chromosphere.
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Question 6
I am Lyosha [343]

Answer:

A. is the correct point.

Explanation:

This is true because no matter how many mL of water is added, the solution only gets more height; the concentration in everything else stays the same, and water doesn't have any concentration. Very confusing, I know. Good luck!

4 0
2 years ago
Fe + H2SO4 = Fe2(SO4)3 + H2
a_sh-v [17]
C (667) that’s the answer boiii
5 0
3 years ago
Suppose a 250. mL flask is filled with 0.30 mol of N_2 and 0.70 mol of NO. The following reaction becomes possible:N_2(g) +O2 →
Inessa [10]

Answer:

0.4 M

Explanation:

Equilibrium occurs when the velocity of the formation of the products is equal to the velocity of the formation of the reactants. It can be described by the equilibrium constant, which is the multiplication of the concentration of the products elevated by their coefficients divided by the multiplication of the concentration of the reactants elevated by their coefficients. So, let's do an equilibrium chart for the reaction.

Because there's no O₂ in the beginning, the NO will decompose:

N₂(g) + O₂(g) ⇄ 2NO(g)

0.30 0 0.70 Initial

+x +x -2x Reacts (the stoichiometry is 1:1:2)

0.30+x x 0.70-2x Equilibrium

The equilibrium concentrations are the number of moles divided by the volume (0.250 L):

[N₂] = (0.30 + x)/0.250

[O₂] = x/0.25

[NO] = (0.70 - 2x)/0.250

K = [NO]²/([N₂]*[O₂])

K = \frac{(\frac{0.70 -2x}{0.250})^2 }{\frac{0.30+x}{0.250}*\frac{x}{0.250} }

7.70 = (0.70-2x)²/[(0.30+x)*x]

7.70 = (0.49 - 2.80x + 4x²)/(0.30x + x²)

4x² - 2.80x + 0.49 = 2.31x + 7.70x²

3.7x² + 5.11x - 0.49 = 0

Solving in a graphical calculator (or by Bhaskara's equation), x>0 and x<0.70

x = 0.09 mol

Thus,

[O₂] = 0.09/0.250 = 0.36 M ≅ 0.4 M

3 0
3 years ago
What is the molar mass of water in the hydrate? FeSO4 • 7H2O
Rainbow [258]
M=7M(H₂O)

M=7*18.015 g/mol = 126.105 g/mol
5 0
3 years ago
What would be the effect on this reaction of increasing the temperature?
Ainat [17]

Answer: D

Explanation: I got it wrong on my test :( and got this answer as correct.

6 0
2 years ago
Read 2 more answers
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