Answer:
6.098M
Explanation:
akording to m1v1/m2v2=n1/n2
The unit expressed in 660 nm of light represents the wavelength of light. If you want to determine the frequency, you use the speed of light to relate the two. The formula is:
c = λν
where
λ is the wavelength
ν is the frequency
c is the speed of light = 3×10⁸ m
Apply SI units:
(3×10⁸ m) = (660×10⁻⁹ m)(ν)
Solving for ν,
<em>ν = 4.55×10¹⁴ s⁻¹</em>
Answer: It is non-spontaneous at all T.
Explanation:
According to Gibb's equation:
= Gibbs free energy = +ve
= enthalpy change = +ve
= entropy change = -ve
T = temperature in Kelvin
= +ve, reaction is non spontaneous
= -ve, reaction is spontaneous
= 0, reaction is in equilibrium
Putting in the values:
Reaction is non spontaneous at all temperatures.
Answer: Concentration of
in the equilibrium mixture is 0.31 M
Explanation:
Equilibrium concentration of
= 0.729 M
The given balanced equilibrium reaction is,
![2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)](https://tex.z-dn.net/?f=2NH_3%28g%29%5Crightleftharpoons%20N_2%28g%29%2B3H_2%28g%29)
Initial conc. x 0 0
At eqm. conc. (x-2y) M (y) M (3y) M
The expression for equilibrium constant for this reaction will be:
3y = 0.729 M
y = 0.243 M
![K_c=\frac{[y]\times [3y]^3}{[x-2y]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5By%5D%5Ctimes%20%5B3y%5D%5E3%7D%7B%5Bx-2y%5D%5E2%7D)
Now put all the given values in this expression, we get :
![K_c=\frac{0.243\times (0.729)^3}{(x-2\times 0.243)^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B0.243%5Ctimes%20%280.729%29%5E3%7D%7B%28x-2%5Ctimes%200.243%29%5E2%7D)
![0.967=\frac{0.243\times (0.729)^3}{(x-2\times 0.243)^2}](https://tex.z-dn.net/?f=0.967%3D%5Cfrac%7B0.243%5Ctimes%20%280.729%29%5E3%7D%7B%28x-2%5Ctimes%200.243%29%5E2%7D)
![x=0.80](https://tex.z-dn.net/?f=x%3D0.80)
concentration of
in the equilibrium mixture = ![0.80-2\times 0.243=0.31](https://tex.z-dn.net/?f=0.80-2%5Ctimes%200.243%3D0.31)
Thus concentration of
in the equilibrium mixture is 0.31 M
120 grams of NaOH means 3 Moles of NaOH because 40 grams (Molecular Weight in grams) is one mole of NaOH.
Each mole of any substance contain Avogadro’s number of molecules ie., 6.022 x (10 to the power 23).
Hence 3 Moles of NaOH contain 3 times of Avogadro’s number of molecules ie., 3 x 6.022 x (10 to the power 23)