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borishaifa [10]
3 years ago
10

What would be a good example of kinetic energy?

Physics
1 answer:
Free_Kalibri [48]3 years ago
7 0

Answer:

3) a skier racing down a hill

Explanation:

Remember kinetic energy is energy which a body possess by virtue of being in motion. So anything that is in motion will gain kinetic energy and lose potential energy. Answer 3 was the only object in motion. Kinetic energy is also named energy of motion.

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What mass of a material with density ρ is required to make a hollow spherical shell having inner radius r1 and outer radius r2?
krok68 [10]

Answer: m=\frac {\rho}{\frac{4}{3} \pi( (r_2)^{3} - (r_1)^{3}) }

It is given that:

Density of material =ρ

radius of inner spherical shell = r_1

radius of outer spherical shell=r_2

we know that the volume of sphere is \frac{4}{3}\pi r^{3}

Volume of the given spherical shell = \frac{4}{3}\pi( (r_2)^{3}-(r_1)^{3})

Then mass of the spherical shell can be calculate as:

Mass, m=density/ volume

m=\frac {\rho}{\frac{4}{3} \pi ((r_2)^{3} - (r_1)^{3}) }


6 0
3 years ago
Work done per unit time :- a. force b. power c. energy d. momentum​
iragen [17]
The Answer: B. Power
7 0
3 years ago
Three identical particles, q1, q2, and q3, each with charge q = 5.00 μC, are placed along a circle of radius r = 2.00 m at angle
wariber [46]

Answer:

11250 N/C

Direction: 0 deg counterclockwise from positive x-axis

Explanation:

q = magnitude of charge on each particle = 5 μC =  5 x 10⁻⁶ C

r = distance of each particle from center of circle = 2 m

E = Magnitude of electric field at the center by each particle

Magnitude of electric field at the center by each particle is given as

E = \frac{kq}{r^{2} }

inserting the values

E = \frac{(9\times10^{9} )(5\times10^{-6})}{2^{2} }\\E = 11.25\times10^{3} NC^{-1}

From the diagram , we see that being equal and opposite, the electric fields due to charge q₁ and q₃ cancel out.

So net electric field at center is only due to charge q₂ direction towards positive x-direction

So

E_{res} = Resultant electric field = 11250 N/C

Direction: 0 deg counterclockwise from positive x-axis

7 0
3 years ago
Một sóng cơ học có tần số 50hz lan truyền dọc theo một sợi dây rất dài biết rằng sau 5 giây sóng truyền được 1 đoạn 25m dọc theo
Oliga [24]

Answer:

10 cm

Explanation:

Được

Tần số = 50 hertz

Khoảng cách đã đi = 25 m

Thời gian đi quãng đường 25 m = 5 giây

Tốc độ của sóng = 25/5 = 5 mét trên giây

Như chúng ta biết

Bước sóng = Vận tốc / tần số

Bước sóng = 5 mét trên giây / 50 trên giây

Bước sóng = 0,1 m = 10 cm

3 0
3 years ago
a person throws a ball in such a way that its speed is zero at one particular point in its path. How did the person throw the ba
Keith_Richards [23]

vertical! or in other words, up!


6 0
4 years ago
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