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ElenaW [278]
3 years ago
6

4 . suppose you are setting up a reaction that requires an iodide salt and are planning to use sodium iodide. however, at the la

st minute you find that you are out of sodium iodide, so you must use potassium iodide instead. will you need to weigh out more, less, or the same mass of potassium iodide in order to get the same number of moles of iodide ions?
Chemistry
1 answer:
xxTIMURxx [149]3 years ago
6 0
You will need to weight out less
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How many grams of Cl2 are in 1.20 x 1024 Cl atoms?
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<h3>Answer:</h3>

70.906 g

<h3>Explanation:</h3>

We are given;

  • Atoms of Chlorine = 1.2 × 10^24 atoms

We are required to calculate the mass of Chlorine

  • We know that 1 mole of an element contains atoms equivalent to the Avogadro's number, 6.022 × 10^23.
  • That is , 1 mole of an element = 6.022 × 10^23 atoms
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But since Chlorine gas is a molecule;

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But, molar mass of Chlorine gas = 70.906 g/mol

Then;

70.906 g Of chlorine gas = 2 × 6.022 × 10^23 atoms

                                          = 1.20 × 10^24 atoms

Thus;

For 1.2 × 10^24 atoms ;

= ( 70.906 g/mol × 1.2 × 10^24 atoms ) ÷ (1.20 × 10^24 atoms)

<h3>=  70.906 g </h3>

Therefore, 1.20 × 10^24 atoms of chlorine contains a mass of 70.906 g

=  

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1. What are the differences between lonic and covalent bonds?
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What happens to the atomic radius when an electron is gained?
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