Answer:
328.1 K.
Explanation:
- To calculate the no. of moles of a gas, we can use the general law of ideal gas: <em>PV = nRT</em>.
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in.
- If n is constant, and have two different values of (P, V and T):
<em>P₁V₁T₂ = P₂V₂T₁</em>
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P₁ = 1.0 atm (standard P), V₁ = 72.1 L, T₁ = 25°C + 273 = 298 K (standard T).
P₂ = 93.6 kPa = 0.924 atm, V₂ = 85.9 L, T₂ = ??? K.
<em>T₂ = P₂V₂T₁/P₁V₁ = </em>(0.924 atm)(85.9 L)(298 K)/(1.0 atm)(72.1 L) <em>= 328.1 K.</em>
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1st one is Science and the 2nd one is Bias
Answer:
Silicates are kind of inert reactively, it could be used as hydrocarbin additives, lubricants and much more.
Completing the Sentences;
1. Carbon
2. insulating
3. Good lubricant and electrically conductive
Explanation:
SiO2 has a peculiar nature. It isn't very reactive. It has a very high melting point. grinding wheels. It is difficult to deform or melt it and its related compounds because its polar covalent (Si–C or Si–O) bonds must be broken, and this requires a large input of energy. It also does not contain any hydrogen, thus it cannot act as a Brønsted–Lowry acid. While not soluble in water, it dissloves in hot concentrated alkali or fused hydroxide.
Silicon metal is made from the reaction of silica (silicon dioxide, SiO2) and carbon materials like coke, coal and wood chips. Silica is typically received in the form of metallurgical grade gravel.
Silicates can be used as solid lubricants, lubricant additives in engine oil, as fume silica grease, rubber materials, waterproofing materials, and caulks.
Fused Silica has extremely good dielectric and insulating properties. For these reasons it is used as an inert, low expansion filler material for epoxy resins in electronic circuits as an insulator.
Answer:
The final molarity of nitrate anion in the solution is 0.258 M.
Explanation:
Mass of barium nitrate 1.73 g
Moles of barium nitrate =
1 mole of barium nitrate gives 2 moles of nitrate ions,then 0.00662 mol of barium nitrate will give :
of nitrate ions
moles of nitrate ion added to the solution = 0.01324 mol
Molarity of the barium nitrate solution = 63.0 mM = 0.063 M
1 mM = 0.001 M
Volume of barium nitrate solution = 100 mL = 0.100 L
1 m L = 0.001 mL
Moles of barium nitrate in the solution = n
Moles of nitrate ion in solution = 2 0.0063 × mol = 0.0126 mol
Total moles og nitrate ions = 0.01324 mol + 0.0126 mol = 0.02584 mol
Final molarity of nitrate anion in the solution.:
The final molarity of nitrate anion in the solution is 0.258 M.