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forsale [732]
2 years ago
6

Hydrogen + copper(II) oxide= copper + steam, which substance is oxidized. explain your answers

Chemistry
1 answer:
Vsevolod [243]2 years ago
4 0
Hydrogen is oxidized. The H2 reactant has an oxidation number of 0 because it’s in its elemental form. In the H2O product, H has an oxidation number of +1. The increase in oxidation number is oxidation.
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Please help this is due tonight
Elenna [48]
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5 0
3 years ago
Suppose that 273 of a substance displaces 26ml of water what is the substance
Llana [10]
273g/25 mL = 10.92 (that's the density)
What has a density of 10.92 grams/mL?  I don't know but I bet it's in your notes or on the worksheet.
3 0
3 years ago
In the formation of a macromolecule, what type of bond would join two amino acid subunits?
luda_lava [24]
I think its an Ionic bond although i am not sure about
8 0
3 years ago
Read 2 more answers
What is penetration? How is it related to shielding? Use the penetration effect to explain the difference in relative orbital en
Whitepunk [10]

Answer: penetration is the ability of an electron in a given orbital to approach the nucleus closely. Shielding refers to the fact that core electrons reduce the degree of nuclear attraction felt by the orbital electrons. Shielding is the opposite of penetration. The most penetrating orbital is the least screening orbital. The order of increasing shielding effect/decreasing penetration is s<p<d<f.

Explanation:

The order of penetrating power is 1s>2s>2p>3s>3p>4s>3d>4p>5s>4d>5p>6s>4f....

Since the 3p orbital is more penetrating than the 3d orbital, it will lie nearer to the nucleus and thus possess lower energy.

5 0
3 years ago
A 25.00 ml sample of hydrochloric acid solution, hcl, is titrated with 0.0512 m naoh solution. the volume of naoh solution requi
Tresset [83]

A 25.00 ml sample of hydrochloric acid solution, HCl, is titrated with 0.0512 m NaOH solution. the volume of NaOH solution required is 21.68 ml  then the molarity of the HCl solution is 0.044 M .

Calculation ,

Formula used : M_{1} V_{1} =M_{2} V_{2}                            ...( i )

Where M is the molarity or concentration and V is the volume in ml .

concentration of hydrochloric acid solution ( M_{1}    ) = ?

concentration of NaOH ( M_{2} ) = 0.0512 M

volume of hydrochloric acid solution  ( V_{1} ) = 25.00 ml

volume of NaOH ( V_{2} ) =  21.68 ml

Putting the value of concentration , volume of both  in equation ( i ) we get .

M_{1}   × 25.00 ml = 0.0512 × 21.68 ml

M_{1}    = 0.0512 × 21.68 ml / 25.00 ml= 0.044 M

to learn more about hydrochloric acid solution please click here ,

brainly.com/question/24586675

#SPJ4

5 0
1 year ago
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