Answer:
=> 2.8554 g/mL
Explanation:
To determine the formula to use in solving such a problem, you have to consider what you have been given.
We have;
mass (m) = 16.59 g
Volume (v) = 5.81 mL
From our question, we are to determine the density (rho) of the rock.
The formula:
Substitute the values into the formula:
= 2.8554 g/mL
Therefore, the density (rho) of the rock is 2.8554 g/mL.
The shape of the organism is a huge factor, as it could fact for a different creature and/or organism every time. For example, a antelope may have a different form or structure of let’s say a spider, as this is the significant factor of ones shape, the first observation.
Secondly, the colors. As different organism come in different areas of reflections of light, it can easily be identified with this certain color and the way that the light reflects on it. This is another form of visual appearance, and important factor in identification.
Lastly, the pattern. As located on the back, the spikes/thread-looking things sticking out plays a huge factor in finding the organism name and/or identifying it. Every organism has a different pattern, humans being a huge one, all different
Observational studies of organisms is significant to our lives, and it’s greatly helped progress our sciences and society.
Answer:
0.25 L of a solution with a molarity of 6M has 6*0.25 = 1.5 moles of the solute. The molar mass of ammonium sulfate is 132.14 g/mole. The mass of 1.5 moles is 132.14*1.5 = 198.21 g. Therefore 198.12 g of ammonium sulfate are required to make 0.25 L of a solution with a concentration of 6M.
Explanation:
Answer:
6) 225.8 g
7) 1.01 g
8) 21.624 g
Explanation:
6) Molar Mass of Lithium Bromine: 86.845
86.845 * 2.6 = 225.8 g
7) Molar Mass of Neon: 20.180
20.180 * 0.05 = 1.01 g
8) Molar Mass of Water Vapor: 18.02
18.02 * 1.2 = 21.624 g
