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2 years ago

The elementary reaction_.

Chemistry

2 answers:

Aleks [24]2 years ago

8 0

A. Converts reactants to products in a single step.

zlopas [31]2 years ago

7 0

Answer:

Explanation:

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true or false an element's reactivity is determined by the number of protons found in an atom of the element

andreyandreev [35.5K]

False... The number of electrons in the outer shell of the atom of the element determines it's reactivity. <span />

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2 years ago

Balance the following equations:

lesya [120]

<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2><h2>_____________________________________</h2>

(I) $N_{2} + 3H_{2} --> 2NH_{3}$

(II) $P_{4} + 5O_{2} --> 2P_{2} O_{5}$

(III) $2NaF + Br_{2} -->2NaBr + F_{2}$

(IV) $2ZnS + 3O_{2} --> 2ZnO + 2SO_2$

(V) $Pb(NO_3)_2 + 2NaCl --> 2NaNO_3 + PbCl_2$

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2 years ago

If a gas has a volume of 1000 ML at a temperature of 23°C and a pressure of 100 mmhg, what is it’s volume under standard conditi

Colt1911 [192]

Answer:

119.7 mL.

Explanation:

From the general law of ideal gases:

where, P is the pressure of the gas.

V is the volume of the container.

n is the no. of moles of the gas.

R is the general gas constant.

T is the temperature of the gas (K).

For the same no. of moles of the gas at two different (P, V, and T):

P₁ = 100.0 mmHg, V₁ = 1000.0 mL, T₁ = 23°C + 273 = 296 K.

P₂ = 1.0 atm = 760.0 mmHg (standard P), V₂ = ??? mL, T₂ = 0.0°C + 273 = 273.0 K (standard T).

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3 years ago

Draw the major product for the reaction of 1-butyne with water in the presence of catalytic TfOH (i.e., CF3SO3H). Then answer th

Mademuasel [1]

Answer:

2-Butanone

Explanation:

From the given information:

The presence of mercury as an acid catalyst brings about the addition of water to the triple bond which yields enol. Then, according to Markownikov's rule and after tautomerism has occurred, we have a methyl ketone ( 2- Butanone) as the product.

The answer regarding the transformation is addition and hydration.

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3 years ago

What is the volume in liters of 321 g of liquid with a density of 0.84 g/mL

Rasek [7]

Density is weight by volume.

First. If you divide the weight by density you can find the volume

Second you must convert the ML in to Liters.

$\frac{321 \frac{g}{1}}{0.84 \frac{g}{mL}} = \frac{321(g)(mL)}{0.84g}=\frac{321mL}{0.84}=382.14mL$

1L=1000ml

$\frac{1L}{1000mL}$

$(382.14mL)( \frac{1L}{1000mL})= \frac{(382.14mL)(L)}{1000mL} =\frac{382.14L}{1000}=0.38214L$

0.38214 Liters.

4 0

3 years ago