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cestrela7 [59]
3 years ago
7

A bullet is fired straight up from ground level for a distance of 1688.3m at a speed of 182 m/s. How long does it take for the b

ullet to stop?
Physics
1 answer:
Vitek1552 [10]3 years ago
3 0
S= 1/2 x 182 x t = 1688.3
t = 1688.3 / 91
time = 18.55 seconds
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In a 5.00 km race, one runner runs at a steady 11.4 km/h and another runs at 14.7 km/h . How long does the faster runner have to
topjm [15]

Answer:

0.0986 h or 5 minutes 55 seconds.

Explanation:

Speed: This can be defined as the rate of change of distance of a body. The S.I unit of speed is m/s. Speed is a scalar quantity, because it can only be represented by magnitude alone.

Mathematically,

Speed = distance/time.

S = d/t ........................... Equation 1

making t  the subject  of the equation

t = d/S ......................... Equation 2

Form the question,

Time taken for the faster runner to reach the finish line

t₁ = d/S₁................... Equation 3

Where t₁ = time taken for the faster runner to reach the finish line, d = distance, S₁ = speed of the faster runner.

Given: d = 5.0 km, S₁ = 14.7 km/h.

Substituting into equation 3

t₁ = 5/14.7

t₁ = 0.340 h

Also,

t₂ = d/S₂................... Equation 4

Where t₂ = time taken for the slower runner to reached the finished line, d = distance, S₂ = speed of the slower runner.

Given: d = 5 km, S₂ = 11.4 km/h.

Substitute into equation 4,

t₂ = 5/11.4

t₂ = 0.4386 h.

The time the faster runner have to wait at the finish line to see the slower runner cross = t₂ - t₁ = 0.4386-0.340

The time the faster runner have to wait at the finish line to see the slower runner cross = 0.0986 h = 5 mins 55 s.

8 0
4 years ago
When an electron in a certain excited energy level in a one-dimensional box of length 2.00 Å makes a transition to the ground st
Fiesta28 [93]

Answer:

Calculate the wavelength associated with an electron with energy 2000 eV.

Sol: E = 2000 eV = 2000 × 1.6 × 10–19 J

5 0
3 years ago
Find a numerical value for ρearth, the average density of the earth in kilograms per cubic meter. use 6378km for the radius of t
Andre45 [30]

Answer:

5501 kg/m^3

Explanation:

The value of g at the Earth's surface is

g=\frac{GM}{R^2}=9.70 m/s^2

where G is the gravitational constant

M is the Earth's mass

R=6378km = 6.378 \cdot 10^6 m is the Earth's radius

Solving the formula for M, we find the value of the Earth's mass:

M=\frac{gR^2}{G}=\frac{(9.81 m/s^2)(6.378\cdot 10^6 m)^2}{6.67\cdot 10^{-11}}=5.98\cdot 10^{24}kg

The Earth's volume is (approximating the Earth to a perfect sphere)

V=\frac{4}{3}\pi r^3 = \frac{4}{3}\pi (6.378\cdot 10^6 m)^3=1.087\cdot 10^{21} m^3

So, the average density of the Earth is

\rho = \frac{M}{V}=\frac{5.98\cdot 10^{24} kg}{1.087\cdot 10^{21} m^3}=5501 kg/m^3

4 0
4 years ago
Read 2 more answers
The capacity of the air to hold water vapor: Group of answer choices 1. decreases with an increase in temperature.2. increases w
Nezavi [6.7K]

Answer:

3. increases with an increase in temperature.

Explanation:

The air more water vapor at higher temperatures because at higher temperatures the air expands and the inter-molecular space increases so the room for water molecules increases.

Warm air keeps the water molecules warm and prevents them from condensing.

The air can hold the moisture only upto its saturation quantity after which the precipitation occurs in the form of rain, snow, hail, sleet etc.

5 0
3 years ago
Read 2 more answers
A ball is dropped from a height of 80m. The time, in seconds, it takes to reach the ground is:__________.
Aleonysh [2.5K]

Answer:

4.04 s

Explanation:

h = vi + 1/2 a t ^2

HERE  h = 80 m , vi = 0 , a =9.81 m/s^2

80 = 0 + 1/2 × 9.81 × t ^2

80 = 4.905 t^2

t^2 = 80/4.905

t ^2 = 16.30988

t = square root of 16.30988

t =  4.0385 s

t = 4.04 s

4 0
3 years ago
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