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Alona [7]
2 years ago
8

In most turbochargers, the lubricating oil comes A. from an internal engine resevoir. B. under pressure through lines in the eng

ine. C. with a light contamination of dirt particles. D. via greased bearings.​
Chemistry
1 answer:
nlexa [21]2 years ago
8 0
I’m not sure, but I think A. from an internal engine reservoir
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What makes an element the same as another element
olganol [36]

Answer:elements cannot be split into two

Explanation:elements are pure substances which cannot be split into two by chemical means

6 0
3 years ago
Describe how chemists use mass as a way of getting a precise estimate of the number of entities in a sample.
jok3333 [9.3K]

Answer:

Explanation:

To start with, the mass of a substance is centered on the amount of particles contained in it.

Mass of a substance measure is the same anywhere it is taken.

In chemistry, the concept of mole is used to find the exact estimate of  the number of entities in a sample.

A mole of substance is quantity that is used to express the number of particles contained in it.

  1 mole of any substance contains the Avogadro's number of particles.

This amount of particles is given as 6.02 x 10²³; the particles can be protons, neutrons, electrons e.t.c.

To find the number of moles;

        Number of moles  = \frac{mass}{molar mass}

       Through this, we clearly ascertain the number of entities in a sample given the mass.

5 0
3 years ago
What is the definition of a Lewis acid?
Vedmedyk [2.9K]

Answer:

Explanation:

Un ácido de Lewis es una especie química que contiene un orbital vacío que es capaz de aceptar un par de electrones de una base de Lewis para formar un aducto de Lewis

3 0
3 years ago
Pentaborane-9, B5H9, is a colorless, highly reactive liquid that will burst into flame when exposed to oxygen. The reaction is 2
mina [271]

<u>Answer:</u> The amount of energy released per gram of B_5H_9 is -71.92 kJ

<u>Explanation:</u>

For the given chemical reaction:

2B_5H_9(l)+12O_2(g)\rightarrow 5B_2O_3(s)+9H_2O(l)

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f_{(product)}]-\sum [n\times \Delta H^o_f_{(reactant)}]

The equation for the enthalpy change of the above reaction is:

\Delta H^o_{rxn}=[(5\times \Delta H^o_f_{(B_2O_3(s))})+(9\times \Delta H^o_f_{(H_2O(l))})]-[(2\times \Delta H^o_f_{(B_5H_9(l))})+(12\times \Delta H^o_f_{(O_2(g))})]

Taking the standard enthalpy of formation:

\Delta H^o_f_{(B_2O_3(s))}=-1271.94kJ/mol\\\Delta H^o_f_{(H_2O(l))}=-285.83kJ/mol\\\Delta H^o_f_{(B_5H_9(l))}=73.2kJ/mol\\\Delta H^o_f_{(O_2(g))}=0kJ/mol

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(5\times (1271.94))+(9\times (-285.83))]-[(2\times (73.2))+(12\times (0))]\\\\\Delta H^o_{rxn}=-9078.57kJ

We know that:

Molar mass of pentaborane -9 = 63.12 g/mol

By Stoichiometry of the reaction:

If 2 moles of B_5H_9 produces -9078.57 kJ of energy.

Or,

If (2\times 63.12)g of B_5H_9 produces -9078.57 kJ of energy

Then, 1 gram of B_5H_9 will produce = \frac{-9078.57kJ}{(2\times 63.12)}\times 1g=-71.92kJ of energy.

Hence, the amount of energy released per gram of B_5H_9 is -71.92 kJ

8 0
3 years ago
Is ink a compound or mixture?
Vladimir79 [104]
A mixture, because it contains multiple dyes and compounds

hopefully i could help ;)
8 0
3 years ago
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