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Aneli [31]
3 years ago
11

Which of the following is considered a transition metal?

Chemistry
2 answers:
tatyana61 [14]3 years ago
4 0
Sodium is considered to be a transitional metal
Brums [2.3K]3 years ago
4 0
Zinc. The rest are main group elements.
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What is the velocity of a plane that traveled 3000 miles from New York to Los Angeles in 5.0 hours?
miss Akunina [59]

Answer:

600 mph

Explanation:

Just divide 3000 by 5.

3 0
3 years ago
Explain how do you would count the sig figs in the following number, 0.00340670, and what is
loris [4]

Answer:

The zeros in front of the 3 show where the decimal is. Then start counting at the 3 to the right. There are 6 sig figs.

Explanation:

3 0
3 years ago
Lead has a density of 11.4 g/cm^3. What is the density in kilograms per cubic meter?
Vikentia [17]

The density in kg/m³ = 1.14 x 10⁴

<h3>Further explanation  </h3>

Density is a quantity derived from the mass and volume  

Density is the ratio of mass per unit volume  

With the same mass, the volume of objects that have a high density will be smaller than objects with a smaller type of density  

The unit of density can be expressed in g/cm³ or kg/m³  

Density formula:  

\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}

ρ = density , g/cm³ or kg/m³  

m = mass  , g or kg

v = volume  , cm³ or m³  

A density of Lead : ρ = 11.4 g/cm³

the density in kg/m³ :

\tt 11.4~\dfrac{g}{cm^3}\times \dfrac{kg}{10^3~g}\times \dfrac{cm^3}{10^{-6}~m^3}=\boxed{\bold{1.14\times 10^4~\dfrac{kg}{m^3}}}

8 0
3 years ago
A student reduces the temperature of a 300 cm3 balloon from 60°c to 30°
FromTheMoon [43]

We can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

T1 / V1 = T2 / V2

V2 = T2 x V1 / T1

V2 = 303.15  x 300 / 333.15

<span>V2 = 272.99 cm³</span>

7 0
3 years ago
Calculate the amount of HCN that gives the lethal dose in a small laboratory room measuring 12.0 ft×15.0 ft×8.60ft.
garik1379 [7]

<u>Given:</u>

Dimensions of the room= 12 ft * 15 ft * 8.60 ft

<u>To determine:</u>

The amount of HCN that gives the lethal dose in the room with the given dimensions

<u>Explanation:</u>

As per the World Health Organization, the lethal dose of HCN is around 300 ppm

300 ppm = 300 mg of HCN/ kg of inhaled air

Volume of air = volume of room = 12 * 15 *8.6 = 1548 ft³

Now,  1 ft³ = 28316.8 cm³

Therefore, the calculated volume of air corresponds to:

1548 * 28316.8 = 4.383 * 10⁷ cm3

Density of air (at room temperature 25 C) = 0.00118 g/cm3

Thus mass of air corresponding to the calculated volume is

Mass = Density * volume = 0.00118 g/cm3 * 4.383 * 10⁷ cm3

= 5.172*10⁴ g = 51.72 kg

Lethal amount of HCN corresponding to 51.72 kg of air would be.

= 51.72 kg air* 300 mg of HCN/1 kg air = 15516 mg

Ans: Lethal dose of HCN = 15.5 g

7 0
3 years ago
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