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3 years ago

The electromagnetic spectrum includes radio waves inferared waves and x rays

Physics

1 answer:

olya-2409 [2.1K]3 years ago

8 0

Answer:

True

Explanation:

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What is it known as when a force is applied to an object for an amount of time?.

alina1380 [7]

You strong to do that

8 0

2 years ago

A car tire is filled with air at pressure 325000 pa at 303 K. When the tire cools,its pressure reduces to 299000 Pa. What is the

max2010maxim [7]

Answer:

new temperature of the tire will be 278.76 K

Explanation:

when the temperature increases, the particles will have greater kinetic energy and also the pressure will be increase for the gas particles.

so when the temperature increases, pressure will also increase and vice versa

T is directly proportional to P

T1 = initial temperature= 303 k

P1= Initial pressure = 325000 pa

T2= Final temperature= ?

P2= Final pressure = 299000 pa

mathematically

P1/T1= P2/T2

T2= P2 x T1/P1

T2 = 299000 x 303/ 325000= 278.76 k

6 0

3 years ago

Read 2 more answers

An electron is located in an electric field of magnitude 600 Newton's per coulomb. What is the magnitude of the electrostatic fo

qaws [65]

Answer:

force on electron will be equal to $9.6\times 10^{-17}N$

Explanation:

We have given magnitude of electric field E = 600 N/C

Charge on electron $e=1.6\times 10^{-19}C$

We have to find the electric force on the electron

Force in electric field is equal to $F=qE$ , here q is charge and E is electric field

So force will be equal to $F=1.6\times 10^{-19}\times 600=960\times 10^{-19}=9.6\times 10^{-17}N$

So force on electron will be equal to $9.6\times 10^{-17}N$

4 0

3 years ago

Read 2 more answers

What is the effect on the force if the mass is increased 3 times?

Andrei [34K]

Answer:

Force will increase 3 times

Explanation:

We know force is directly porpotional to acclereation, with the constant, m mass.

$f = ma$

So if we mass is increased 3 times the force will increase 3 times.

5 0

2 years ago

Use F = 1/T as your basis:

skelet666 [1.2K]

Time Period=T=2.5×10^{-3}s

Now

Frequency:-

$\\ \rm\rightarrowtail \nu=\dfrac{1}{T}$

$\\ \rm\rightarrowtail \nu=\dfrac{1}{2.5\times 10^{-3}}$

$\\ \rm\rightarrowtail \nu=0.4\times 10^{3}$

$\\ \rm\rightarrowtail \nu=400Hz$

6 0

2 years ago