Answer: Approximately 22 cm
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Explanation:
The unstretched spring is 12.0 cm long. When adding a load of 5.0 N, it stretches to 15.0 cm. This is a displacement of 15.0 - 12.0 = 3.0 cm, which is the amount the spring is stretched.
Convert this displacement to meters (so that it fits with the meters unit buried in Newtons).
3.0 cm = (3.0)/100 = 0.03 m
Apply Hooke's Law to find the spring constant k
F = -kx
5.0 = -k*(0.03)
k = -(5.0)/(0.03)
k = -166.667 approximately
Now we must find the displacement x when F = 15 newtons
F = -kx
-kx = F
x = F/(-k)
x = -F/k
x = -15/(-166.667)
x = 0.089 approximately
x = 0.1
The displacement to one decimal place is about 0.1 meters, which converts to 100*0.1 = 10 cm
So the spring will be stretched to about 12cm+10cm = 22 cm
We have that the force between the two charged objects is mathematically given as
F=2.349N
<h3>Magnitude of the force between two charged objects.</h3>
Question Parameters:
Two spheres carry a charge of 1x10^-7 C.
Their centers are <u>separated</u> by 0.7m.
Generally the equation for the Force is mathematically given as
Therefore
F=2.349N
For more information on Force visit
brainly.com/question/26115859
Answer:
The point through which the Whole mass of the body acts, irrespective of the position of the body, is known as centre of gravity (briefly written as c.g.). ... Mass affects the centre of gravity of the object.
Explanation:
