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makvit [3.9K]
3 years ago
7

List some of the most common injuries that can occur from sports.Explain the importance of following the rules while participati

ng in sports.
Physics
2 answers:
FrozenT [24]3 years ago
7 0
The most common injuries from sports could be ankle sprains, concussion, bone fractures, kneetears, hamstring strains, and groin strain.
MakcuM [25]3 years ago
6 0

Answer:

Answers will vary. Sample response : The most common injuries from sports include ankle sprains, concussion, bone fractures, knee tears, hamstring strains, and groin strain.

Explanation:

Sample response, EDGE 2021

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Edgar is walking 0.5 M/S toward the back of a train that is traveling forward at 6.0 M/S west. What is Edgars velocity relative
iragen [17]

Answer:

Just in 1 dimension  

Vpg = Vps + Vsg

Where

Vpg= relative to the ground

Vps= person relative to the ship

Vsg= ship relative to the ground

Vpg= Vps+Vsg ;

Vpg= 0.5 + 6  

Vpg= 6,5 m/s

8 0
4 years ago
A heater has resistance of 10 ohms. It operates at 120 volts. a. What is the current through the heater?​
Natali5045456 [20]

Answer:

  I = 12 A

Explanation:

For this exercise we use the relationship that voltage is proportional to the product of current and resistance

           V = I R

            I = V / R

             

let's calculate

            I = 120/10

            I = 12 A

4 0
3 years ago
URGENT!!!!! If a 6 Ω resistor is in a circuit connected to a voltage source, and the current through the circuit is 2 amps, what
Eduardwww [97]

Answer:

Explanation:

according to ohms law we know that

v=IR

given current =2 amps

given resistance =6Ω

so voltage is

v=2*6 =12 V

3 0
4 years ago
If you travel 40 miles east and then turn around and drive 12 miles west, the displacement is?
AVprozaik [17]
To find how far east we drove (This is the displacement), we simple subtract 12 from 40.
An easy way to do this in your head is to round 12 down to 10, subtract 10 from 40, then subtract the remaining 2. This should result in an answer showing that you drove 28 miles east.
6 0
3 years ago
Read 2 more answers
The driver of a car traveling 110 km/h slams on the brakes so that the car undergoes a constant acceleration, skidding to a comp
Ber [7]

Answer: -6.80\ ms^{-2}

Explanation:

We know that the formula for acceleration is given by:

a=\dfrac{v-u}{t} , where v = Final velocity

u= Initial velocity

Given :  The driver of a car traveling 110 km/h slams on the brakes so that the car undergoes a constant acceleration.

i.e. u=   110 km/h =\dfrac{110\times1000}{3600}\approx35.6\ m/s  [∵  1 km= 100 meters and 1 hour = 3600 seconds]

v=  0  m/s ( At brake , final velocity becomes 0)

t=4.5 seconds  

Substitute all the values in the formula , we get

a=\dfrac{0-30.56}{4.5}\approx-6.80\ ms^{-2}

Hence, the average acceleration of the car during braking is -6.80\ ms^{-2}.

5 0
3 years ago
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