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3 years ago

I WILL MARK YOU THE BRAINLIEST NO LINKS

Physics

1 answer:

aivan3 [116]3 years ago

6 0

Answer:

Archimedes' Principle

Explanation:

Its because Archimedes' Principle states "that the buoyant force on an object is equal to the weight of the fluid displaced by the object.... If you want to know the buoyant force on an object, you only need to determine the weight of the fluid displaced by the object."

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Define sporulation and fragmentation

Andrei [34K]

Answer:

Sporulation

the formations of spores from vegetative cells during unfavorable environmental conditions

Fragmentation

The asexual reproduction, where the body of the organism breaks into smaller pieces

5 0

3 years ago

Read 2 more answers

The Earth's magnetic field is approximately 0.5 Gauss. What is the magnetic energy density of this field

ser-zykov [4K]

Answer:

The magnetic energy density is $E_B = 9.95 *10^{-4} \ J/m^3$

Explanation:

From the question we are told that

The earths magnetic field is $B = 0.5 \ Gauss$

Now

$1 \ Gauss \to 1 *10^{-4} \ T$

=> $0.5 \ Gauss \to x T$

$x = \frac{0.5 * 1*10^{-4}}{1}$

$x = B= 5.0 *10^{-5} \ T$

Generally the magnetic energy density is mathematically represented as

$E_B = \frac{B^2}{ 2 * \mu_o }$

Here $\mu_o$ is the permeability of free space with a constant value

$\mu_o = 4\pi * 10^{-7} N/A^2$

substituting values for equation above

$E_B = \frac{(5*10^{-5})^2}{ 2 * 4\pi * 10^{-7} }$

$E_B = 9.95 *10^{-4} \ J/m^3$

5 0

3 years ago

Anna35 [415]

Answer:

430.

Explanation:

If we know that 0.5 is half of a whole number, then we can simply understand that we need to 215 x 2 to get our answer.

3 0

3 years ago

Some runners have just started a race. They began at rest and are getting faster.What statement best describes the motion of the

olasank [31]

Answer:

Explanation:

8 0

3 years ago

I need help in my physics class and show me how it’s done

Korolek [52]

If we have the angle and magnitude of a vector A we can find its Cartesian components using the following formula

$A_x = |A|cos(\alpha)\\\\A_y = |A|sin(\alpha)$

Where | A | is the magnitude of the vector and $\alpha$ is the angle that it forms with the x axis in the opposite direction to the hands of the clock.