Option C
Plants, cellular respiration accurately represents a carbon source and the process that releases carbon from that source
<u>Explanation:</u>
Every existing body supplies CO2 off while they evoke power from their food through cellular respiration. Plants and creatures present off CO2 while living and respiring and during lifeless and rotting. Plants are significant carbon sinks, gaining up enormous volumes of CO2 through the manner of photosynthesis.
While plants also discharge CO2 during the means of respiration, the volume of CO2 exercised up by plants by photosynthesis and discharged by exhalation approximately matches out. Volcanic action, forest wildfires, and diverse anthropological exercises deliver carbon.
Answer: 26.8 kJ of energy is needed to vaporize 75.0 g of diethyl ether
Explanation:
First we have to calculate the moles of diethyl ether
As, 1 mole of diethyl ether require heat = 26.5 kJ
So, 1.01 moles of diethyl ether require heat = 
Thus 26.8 kJ of energy is needed to vaporize 75.0 g of diethyl ether
The balanced equation for the above reaction is as follows
C₆H₁₂O₆(s) + 6O₂(g) --> 6H₂O(g) + 6CO₂<span>(g)
the limiting reactant in the equation is glucose as the whole amount of glucose is used up in the reaction.
the amount of </span>C₆H₁₂O₆ used up - 13.2 g
the number of moles reacted - 13.2 g/ 180 g/mol = 0.073 mol
stoichiometry of glucose to CO₂ - 1:6
then number of CO₂ moles are - 0.073 mol x 6 = 0.44 mol
As mentioned this reaction takes place at standard temperature and pressure conditions,
At STP 1 mol of any gas occupies 22.4 L
Therefore 0.44 mol of CO₂ occupies 22.4 L/mol x 0.44 mol = 9.8 rounded off - 10.0 L
Answer is B) 10.0 L CO₂
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