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dimulka [17.4K]
3 years ago
12

Which statements correctly describe the formula or name of a compound? Select all that apply.

Physics
2 answers:
PtichkaEL [24]3 years ago
8 0

Answer:

The formula of nitrogen trifluoride is NF 3

The formula of ammonia is NH3

The formula of magnesium hydroxide is Mg(OH)2

Explanation:

The formula of a compound refers to the correct representation of the compound using appropriate chemical symbols.

The formula of a compound is derived from the symbols of its constituent elements. The formula of the compound must correctly show the number of atoms of each element in one formula unit of the compound.

In the answer section, the correct names or formulas of some compounds have been shown

liraira [26]3 years ago
8 0

Answer:

A. The formula of nitrogen trifluoride is NF3.

B. The formula of ammonia is NH3.

D. The formula of calcium chloride is CaCI2.

H. The formula of magnesium hydroxide is Mg(OH)2.

Explanation:

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Read 2 more answers
What is (Fnet3)x, the x-component of the net force exerted by these two charges on a third charge q3
Pachacha [2.7K]

This question is incomplete, the complete question is;

Coulomb's law for the magnitude of the force F between two particles with charges Q and Q' separated by a distance d is

|FI = |QQ'I / d²

where K = 1/4π∈0, and

∈0 = 8.854 × 10⁻¹² C²/(N.m²) is the permittivity of free space.

Consider two point charges located on the x-axis:

one charge, q₁ = -18.5 nC, is located at

x₁ = -1.715m; the charge q₂ = 30.5 nC, is at the origin ( x₂=0 )

What is (Fnet3)x, the x-component of the net force exerted by these two charges on a third charge q₃ = 51.0 nC placed between q₁ and q₂ at x₃ = -1.085 m ?

Answer: (Fnet3)x = -3.3287 × 10⁻⁵ N

Explanation:

Given that;

Q₁ = -18.5 nC       Q₃ = 51 nC        Q₂ = 30.5 nC

x₁ = - 1.715m         x₃ = - 1.085m     x₂ = 0

Now

x - component of Net force on charge Q₃ is

(Fnet3)x = -K|Q₁I|Q₃I / r₁3² - -K|Q₂I|Q₃I / r₂3²

(Fnet3)x = -(9×10⁹)(51×10⁻⁹) [ 18.5 / ((-1.085 + 1.715)²) + (30.5 / (-1.085)² ] × 10⁻⁹

(Fnet3)x = -3.3287 × 10⁻⁵ N

6 0
3 years ago
Please i need answer for part d
matrenka [14]
It is c that’s what it is that’s the answer
4 0
2 years ago
A proton moves through a magnetic field at 26.7 % 26.7% of the speed of light. At a location where the field has a magnitude of
iogann1982 [59]

Answer:

8.64283\times 10^{-14}\ N

Explanation:

q = Charge of proton = 1.6\times 10^{-19}\ C

v = Velocity of proton = 0.267\times c

c = Speed of light = 3\times 10^8\ m/s

B = Magnetic field = 0.00687 T

\theta = Angle = 101^{\circ}

Magnetic force is given by

F=qvBsin\theta\\\Rightarrow F=1.6\times 10^{-19}\times (0.267\times 3\times 10^8)\times 0.00687\times sin101\\\Rightarrow F=8.64283\times 10^{-14}\ N

The magnetic force acting on the proton is 8.64283\times 10^{-14}\ N

4 0
3 years ago
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