Answer:
grams of iron = 2262.4 g
Explanation:
The balanced chemical equation should be represented first.
2Al + Fe2O3 → Al2O3 + 2Fe
find the limiting reactants by converting to moles.
covert 1.64 kg to grams = 1640 g
moles = mass/molar mass = 1640/27 = 60.7407407407 moles
60.7407407407 × 1 mol-rxn /2 = 30.37 mol-rxn
The limiting reactant is Fe2O3 Therefore it will determine the yield of Iron
2Al + Fe2O3 → Al2O3 + 2Fe
molar mass of Fe2O3 = 56 × 2 + 16 × 3 = 112 + 48 = 160
g
atomic mass of iron = 56
mass of iron in the reaction = 56 × 2 = 112 g
moles = mass/molar mass
mass = moles × molar mass
mass = 20.2 × 160 = 3232 g
if 160 g of Fe2O3 give 112 g of iron
3232
g of Fe2O3 will give ? grams of iron
grams of iron = 3232 × 112/ 160
grams of iron = 361984
/160
grams of iron = 2262.4 g
