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mixer [17]
3 years ago
6

The part of a longitudinal wave where the particles are spread apart is called a______?

Physics
1 answer:
Zielflug [23.3K]3 years ago
3 0
The answer is Rarefactions.

These are the parts of a wave that are further apart and the ones that are close together are called compressions.

I don’t think it is any of the choices stated above!
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Three oxygen isotopes
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Stable isotopes, radioisotopes, oxygen

6 0
3 years ago
An what would be needed to change an objects state of motion
VladimirAG [237]

Inertia: tendency of an object to resist changes in its velocity. An object at rest has zero velocity - and (in the absence of an unbalanced force) will remain with a zero velocity. Such an object will not change its state of motion (i.e., velocity) unless acted upon by an unbalanced force.

~done by cessly420

mark brainliest please

hope this helped   :)

8 0
4 years ago
The wind blows because of____.
seraphim [82]
The wind blows because of____.a. Low pressure and high pressure

b. Convection in together atmosphere.

c. Uneven hearing by the sun
*uneven 'hearing' is not a real thing. However there is an uneven 'heating' of the sun

d. All of the above

Answer:
If C is a typo, the answer is D.all of the above.
3 0
3 years ago
Read 2 more answers
What are the answers please help
aleksandr82 [10.1K]

Answer:

a.) The main scale reading is 10.2cm

b.) Division 7 = 0.07

c.) 10.27 cm

d.)  10.31 cm

e.)  10.24 cm  

Explanation:

The figure depicts a vernier caliper readings

a.) The main scale reading is 10.2 cm

The reading before the vernier scale

b.) Division 7 = 0.07

the point where the main scale and vernier scale meet

c.) The observed readings is

10.2 + 0.07 = 10.27 cm

d.) If the instrument has a positive zero error of 4 division

correct reading = 10.27 + 0.04 = 10.31cm

e.)  If the instrument has a negative zero error of 3 division

correct reading = 10.27 - 0.03 = 10.24cm  

3 0
3 years ago
A bullet with a mass 2.25g is fired up into the air with a velocity of 187.5 m/s. What is the maximum height of the bullet
Ksivusya [100]

Answer:

1793.7m

Explanation:

From the principle of conservation of energy; the kinetic energy substended by the object equals the potential energy sustain by the object when it gets to its maximum position.

Now the kinetic energy; is

K.E = 1/2 × m × v2

Where m is mass

v is velocity

Hence.

K.E = 1/2 × 2.25 × (187.5)^2

Now this should be same with the potential energy which is given as;

P.E = m× g× h

Where m is mass of object

g is acceleration of free fall due to gravity = 9.8m/S2

h is maximum height substain by the object.

Hence P.E = 2.25 × 9.8 × h

From the foregoing analysis of energy conversation it implies;

1/2 × 2.25 × (187.5)^2 =2.25 × 9.8 × h

=> 1/2 × (187.5)^2 = 9.8 × h

=>1/2 × (187.5)^2 / 9.8 = h

=> 1793.69m = h

h= 1793.69m

h =1793.7m to 1 decimal place

3 0
3 years ago
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