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2 years ago

The part of a longitudinal wave where the particles are spread apart is called a______?

1 answer:

3 0

The answer is Rarefactions.

These are the parts of a wave that are further apart and the ones that are close together are called compressions.

I don’t think it is any of the choices stated above!

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Two identical resistors are connected first in series and second in parallel. The equivalent resistances of the two types of con

trasher [3.6K]

Answer:

$\frac{R_{s} }{R_{p} } =\frac{R_{1} }{R_{2} }+\frac{R_{2} }{R_{1} } +2$

Explanation:

We have series and parallel combination of two resisters $R_{1}$ and $R_{2}$ .

Series combination is

$R_{s}= R_{1}+R_{2}$ and Parallel is $R_{p} = (\frac{1}{R_{1}}+\frac{1}{R_{2}} )^-1$

Now dividing series equivalent resistance by parallel resistance gives us

$\frac{R_{s} }{R_{p} } =\frac{R_{1} }{R_{2} }+\frac{R_{2} }{R_{1} } +2$ .

Note! series Combination is simply superposition of two elements (resisters in this case ) in a circuit.

4 0

3 years ago

A rolling ball has an initial velocity of 1.6 meters per second. if the ball has a constant acceleration of 0.33 meters per seco

lukranit [14]

We have:

Initial velocity (u) = 1.6 m/s
Constant acceleration (a) = 0.33 m/s²
Time (t) = 3.6 sec

There are five constant acceleration equations that would help us to find the velocity:

$v=u+at$
$s=ut+ \frac{1}{2}at^2$
$s= \frac{1}{2}(u+v)t$
$v^2=u^2+2as$
$s=vt- \frac{1}{2}at^2$

Since we have $u, a, t$ and we want $v$
We will use the first formula $v=u+at$

$v=1.6+(0.33)(3.6)$
$v= 2.788$ m/s

7 0

3 years ago

91.0x26x504 ...............

Hoochie [10]

Answer:

1192464

Explanation:

91.0 times 26 = 2366

2366 times 504 = 1192464

7 0

3 years ago

Read 2 more answers

Carbon dioxide in a piston-‐‐cylinder is expanded in a polytropic manner. The initialtemperature and pressure are 400 K and 550

Arisa [49]

Answer:

q_poly = 14.55 KJ/kg

Explanation:

Given:

Initial State:

P_i = 550 KPa

T_i = 400 K

Final State:

T_f = 350 K

Constants:

R = 0.189 KJ/kgK

k = 1.289 = c_p / c_v

n = 1.2 (poly-tropic index)

Find:

Determine the heat transfer per kg in the process.

Solution:

-The heat transfer per kg of poly-tropic process is given by the expression:

q_poly = w_poly*(k - n)/(k-1)

- Evaluate w_poly:

w_poly = R*(T_f - T_i)/(1-n)

w_poly = 0.189*(350 - 400)/(1-1.2)

w_poly = 47.25 KJ/kg

-Hence,

q_poly = 47.25*(1.289 - 1.2)/(1.289-1)

q_poly = 14.55 KJ/kg

4 0

3 years ago

PLEASE HELP ASAP!!

Stells [14]

Its B: reduce the amount of energy needed to do the work by putting the work onto something else

3 0

3 years ago

Read 2 more answers