D. Nebulas is a cloud of dust,
B. Protostars & A. Cepheid variables have longer pulsation periods.
Whereas, C. RR Lyrae variables have pulsation periods between 1.5 hours and 1.2 days. So the answer is C.
Answer:
voltage and zero
Explanation:
I don't know i just did the Edg question
Answer:
The first situation is impossible.
Explanation:
"An object has constant non-zero velocity and changing acceleration."
Not possible, acceleration is the change of velocity. For velocity to remain constant the acceleration must remain zero. If acceleration is changing it might be zero at some point, but will not remain zero, so the velocity will change.
"An object has zero velocity but non-zero acceleration."
An object might have a velocity of zero at some point while under an acceleration. An example of this is an object that is thrown upwards. At the top of the trajectory it will have a velocity of zero but will be under the acceleration of gravity.
"An object has constant non-zero acceleration and changing velocity."
This is what any object in free fall do.
"An object has velocity directed east and acceleration directed east."
No problem with that.
"An object has velocity directed east and acceleration directed west."
No problem with that, it will reduce its velocity.
Answer:
c. 100 N
Explanation:
= mass of each = 55 kg
= Time period of rotation = 7.0 sec
Angular frequency is given as
![w = \frac{2\pi }{T} \\w = \frac{2(3.14) }{7}\\w = 0.897 rads^{-1}](https://tex.z-dn.net/?f=w%20%3D%20%5Cfrac%7B2%5Cpi%20%7D%7BT%7D%20%5C%5Cw%20%3D%20%5Cfrac%7B2%283.14%29%20%7D%7B7%7D%5C%5Cw%20%3D%200.897%20rads%5E%7B-1%7D)
= Diameter of the merry-go-round = 4.5 m
Radius of the merry-go-round is given as
![r = \frac{d}{2} = \frac{4.5}{2} = 2.25 m](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7Bd%7D%7B2%7D%20%3D%20%5Cfrac%7B4.5%7D%7B2%7D%20%3D%202.25%20m)
Magnitude of outward force is same as the centripetal force and is given as
![F = m r w^{2} = (55) (2.25) (0.897)^{2} \\F = 100 N](https://tex.z-dn.net/?f=F%20%3D%20m%20r%20w%5E%7B2%7D%20%3D%20%2855%29%20%282.25%29%20%280.897%29%5E%7B2%7D%20%5C%5CF%20%3D%20100%20N)
Answer:
<u>According </u><u>to</u><u> the</u><u> </u><u>Given</u><u> Statement</u><u> </u>
Canon fires directly upwarda at 150m/s ( Initial speed, u )
Acceleration due to gravity is 10m/s²
Since Cannon ball reach it maximum height so its final velocity v will be 0 m/s .
Using Kinematic Equation
On substituting the value we get
➥ 0 = 150 + 10 × t
➥ 150 = 10 × t
➥ 150/10 = t
➥ 15 s = t
So, it will take 15 seconds .