The correct answer is B. -4<x<2.
This is because the domain is looking for the values of x that can be used in the function. In the picture below, you will notice that the leftmost point is at x = -4. This is as low as the x value goes. The rightmost point is at x = 2, which is as large as the x value gets. Therefore the domain is between those two numbers.
Answer:
i need more information on this
Answer:
He should have moved to the right.
Step-by-step explanation:
Ken moved 7 to the right which is correct because he needs to get 7º higher, but when he moved 2º to the left that would be a temperature decrease which is is incorrect.
Answer:
17
Step-by-step explanation:
USING BIDMAS (Brackets Indices Division Multiplication Addition Subtraction)
6 − (9 − 2) + 3 × 6
9-2=7
3x6=18
6-7+18=17
Answer:
6 ft
Step-by-step explanation:
Given that:
Length of rectangular banner = 18 ft
Total trim of banner available = 48 ft
To find:
Possible widths of the banner = ?
Solution:
Maximum trim available of the banner around the entire border of the banner = 48 ft
i.e. we are given the total perimeter of the rectangular banner.
Formula for perimeter of a rectangle is given as:
![Perimeter = 2 \times (Length + Width)](https://tex.z-dn.net/?f=Perimeter%20%3D%202%20%5Ctimes%20%28Length%20%2B%20Width%29)
Putting the values of perimeter and length to find the value of width.
![48 = 2 \times (18 + Width)\\\Rightarrow 48 =36+2 \times Width\\\Rightarrow 2 \times Width = 48-36\\\Rightarrow 2 \times Width = 12\\\Rightarrow \bold{Width = 6\ ft}](https://tex.z-dn.net/?f=48%20%3D%202%20%5Ctimes%20%2818%20%2B%20Width%29%5C%5C%5CRightarrow%2048%20%3D36%2B2%20%5Ctimes%20Width%5C%5C%5CRightarrow%202%20%5Ctimes%20Width%20%3D%2048-36%5C%5C%5CRightarrow%202%20%5Ctimes%20Width%20%3D%2012%5C%5C%5CRightarrow%20%5Cbold%7BWidth%20%3D%206%5C%20ft%7D)
So, width possible is <em>6ft.</em>