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dem82 [27]
3 years ago
12

Has anyone done IXL N.2 7th grade, can you help me!!!

Mathematics
1 answer:
ziro4ka [17]3 years ago
6 0
Okay... let’s see if I remember this! So... first off, convert the whole number into a fraction. To do this, we would need to multiply the number (20) by 2, since the denominator is 2, and then add it to the 1/2 we already have.

= 41/2 × 3/4

Then, put the fractions formula for multiplication into play... (numerators on top, denominators on bottom)

41 × 3
= ————
2 × 4

This would equal 123/8.

Now, we aren’t done yet. To get our final answer, we would to simplify 123/8 to the point where it can’t be any more simple. (For example, if we had 2/2, we would have to simplify that because 2/2 = 1. We wouldn’t be able to simplify the 1 any more than that, making 1 the final answer.) I’ll just do the math for you here. 123/8 simplified completely is 15 3/8.

( 123/8 = 15 3/8.)

I kind of went into detail just in case you were having trouble with these kinds of problems, which I hope isn’t too much of a problem!! Have a good day and I hope this helps :)
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2 years ago
∠1 and ∠2 are complementary angles.<br><br> m∠1 = 72°<br><br> What is the measure of ∠2?
Sidana [21]

The required value of is m∠2 = 18°.

Given that,

First complementary adjacent angel m∠1 = 72°

We have to find,

Second complementary adjacent angle m∠2.

According to the question,

In geometry, the two angles are said to be complementary angles if they add up to 90 degrees.

Such as,  m∠1 + m∠2 = 90°.

Where, m∠1 = 72°

Putting the value of m∠1 = 72° in the equation,

72° + m∠2 = 90°

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m∠2 = 18°

Hence, The required value of is  m∠2 = 18°.

For more information about Complementary adjacent angles click the link given below.

brainly.com/question/24502946

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|−12| = 12<br><br><br> True or False
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Step-by-step explanation:

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have a nice day :)

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The length of a parallelogram exceeds its breadth by 30 cm. If the perimeter of the parallelogram is 2 m 60 cm, find the length
Nuetrik [128]

\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}

\longrightarrow \sf{2(1 + b) = 260}

\longrightarrow \sf{2(x+30+x) = 260}

\longrightarrow \sf{ 2x+30 = \dfrac{260}{20} }

\longrightarrow \sf{2x + 30 =130}

\longrightarrow \sf{2x = 130 - 30}

\longrightarrow \sf{2x = 100}

\longrightarrow \sf{x=  \dfrac{100}{2} }

• \longrightarrow \sf{b= \underline{50cm}}

\longrightarrow \sf{= x + 30}

\longrightarrow \sf{= 50 + 30}

• \longrightarrow \sf{ \underline{80cm}}

\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}

\large\bm{Breadth= \: 50cm}

\large\bm{Length= \: 80cm}

3 0
1 year ago
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