Has anyone done IXL N.2 7th grade, can you help me!!!

Mathematics

1 answer:

ziro4ka [17]3 years ago

6 0

Okay... let’s see if I remember this! So... first off, convert the whole number into a fraction. To do this, we would need to multiply the number (20) by 2, since the denominator is 2, and then add it to the 1/2 we already have.

= 41/2 × 3/4

Then, put the fractions formula for multiplication into play... (numerators on top, denominators on bottom)

41 × 3
= ————
2 × 4

This would equal 123/8.

Now, we aren’t done yet. To get our final answer, we would to simplify 123/8 to the point where it can’t be any more simple. (For example, if we had 2/2, we would have to simplify that because 2/2 = 1. We wouldn’t be able to simplify the 1 any more than that, making 1 the final answer.) I’ll just do the math for you here. 123/8 simplified completely is 15 3/8.

( 123/8 = 15 3/8.)

I kind of went into detail just in case you were having trouble with these kinds of problems, which I hope isn’t too much of a problem!! Have a good day and I hope this helps :)

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Mandy is building a rectangular garden pond with the area of 12ft^2. The length of pool needs to be 2 ft more than twice the wid

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The length of rectangular pool is 6 ft and width of rectangular pool is 2 ft.

Step-by-step explanation:

Given,

Area of rectangular pool = 12 square feet

Let,

Width of pool = w

Length of pool = l = 2w+2

Area = Length * Width

$12=(2w+2)*w\\12=2w^2+2w\\2w^2+2w-12=0$

Dividing each term by 2;

$\frac{2w^2}{2}+\frac{2w}{2}-\frac{12}{2}=0\\w^2+w-6=0\\w^2+3w-2w-6=0\\w(w+3)-2(w+3)=0\\(w+3)(w-2)=0\\$

Either,

w+3 = 0 => w=-3

Or,

w-2=0 =>w=2

As width cannot be negative, therefore,

Width of rectangular pool = 2 ft

Length of rectangular pool = 2w+2 = 2(2)+2 = 4+2 = 6 ft

The length of rectangular pool is 6 ft and width of rectangular pool is 2 ft.

Keywords: rectangle, area

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3 years ago

A rectangle has a length of 45 inches less than 4 times its width. if the area of the rectangle is 3325 square inches, find the

Maru [420]

The length of the rectangle is based on its width, so let's call width w and put the length in terms of the width. We are told that the width is 45 less than 4 times the width, so the length is 4w - 45. Area is found by multiplying length times width and we are given the area as 3325. So we will set up length times width and solve for w, which we will then use to solve for l. 3325 = (4w - 45)(w). Multiplying out we have $3325=4w^2-45w$ . Move the constant over by subtraction and then we will have a quadratic that can be factored to solve for w. $4w^2-45w-3325=0$ . We would put that through the quadratic formula to solve for w. When we do that we get that w = 35 and w = -23.75. The 2 things in math that will never EVER be negative is time and distance/length, so -23.75 is out. That means that the width is 35. The length is 4(35) - 45 which is 95. The dimensions of your rectangle are length is 95 and width is 35. There you go!