Im not sure if this is physics or mathematics. but if 300 msec then per minute this will equal to 300 X 60 sec =18000 m per minute
The echo is weaker than the original sound since the echo has a smaller amplitude than the original sound because sound spreads and its intensity decreases with distance. For example, when the sound from a speaker is heard and is compared to its echo, the echo heard has a lower amplitude than the actual sound.
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Answer:
1248 ft/ sec
Explanation:
Let Q be the position of the observer and let A be the launch point.
Let B = B(t) be the position of the rocket at time t
Also; Let y = y (t)
Let QA be the height of the rocket at time t
We are to find the at a certain time(t) when the distance from Q to the observer is 13000
If we assume an imaginary right-angle triangle QAB ,
Let h be the length of the hypotenuse QB, By using pythagoras Theorem; we have :
h² = 12000² + y²
Differentiating both sides with respect to t ; we have:
----- Equation (1)
where h = 13000
= 480
Replacing it into above equation to find ; we have:
13000 × 480 = 5000 ×
=
= 1248 ft/sec
∴ The rocket is rising fast at the rate of 1248 feet per second.
Liquids evaporate faster as they heat up and more particles have enough energy to break away. The particles need energy to overcome the attractions between them. ... Eventually even particles in the middle of the liquid form bubbles of gas in the liquid. At this point the liquid is boiling and turning to gas.