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Mazyrski [523]
2 years ago
8

The passage helps the reader to draw conclusions about which character's perspective? ºAlec ºAlice ºAlec's father ºAlec's mother

Physics
2 answers:
spayn [35]2 years ago
7 0

Answer:

a

Explanation:

i did it on e d g e n u i t y

TiliK225 [7]2 years ago
4 0

Answer:

I think it might be A: Alec but tell me if I'm wrong

Explanation:

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do y’all think a toxic relationship is good ? like me and him are on and off one minute i say something wrong and BOOM he says b
ziro4ka [17]

Answer:

A toxic relationship is the worst thing someone could have,because people need to learn to chill out.

Explanation:

5 0
3 years ago
A metal sphere with a mass of 0.026 kg rolls along a friction-less surface at 3.7 m/s and strikes a stationary sphefe having a m
zubka84 [21]

The force applied to the second ball by the first ball is 6.734 × 10^-4 N.

<h3>What is impulse of force?</h3>

The impulse of force is defined as the sum of the average force and the duration it is applied.

If the mass of the item remains constant, the impulse of force equals the change in momentum of the object.

Given that:  mass of a metal sphere: m = 0.026 kg.

Initial speed of the sphere: u = 3.7 m/s.

When the sphere stops completely, its change in momentum = mu - 0

= 0.026×3.7 N-s.

= 0.0962 N-s.

As the spheres are in contact for 0.007s before the second sphere is shot off down the track, the force applied  to the second ball =

change in momentum of 1st ball × time of contact

= 0.0962 × 0.007 N

= 0.0006734 N

= 6.734 × 10^-4 N.

Hence,  the force applied  to the second ball is  6.734 × 10^-4 N.

Learn more about impulse force here:

brainly.com/question/29787329

#SPJ1

7 0
1 year ago
A balloon is rising vertically upwards at a velocity of 10m/s. When it is at a height of 45m from the ground, a parachute bails
harina [27]

(a) 30.9 m

Let's analyze the motion of the parachutist. Its vertical position above the ground is given by

y=h+ut+\frac{1}{2}gt^2

where

h = 45 m is the initial height

u = 10 m/s is the initial velocity (upward)

t is the time

g = -9.8 m/s^2 is the acceleration of gravity (downward)

Substituting t=3 s , we find the height of the parachutist when it opens the parachute:

y=45 m+(10 m/s)(3 s)+\frac{1}{2}(-9.8 m/s^2)(3 s)^2=30.9 m

(b) 44.1 m

Here we have to find first the height of the balloon 3 seconds after the parachutist has jumped off from it. The vertical position of the balloon is given by

y = h + ut

where

h = 45 m is the initial height

u = 10 m/s is the initial velocity (upward)

t is the time

Substituting t = 3 s, we find

y = 45 m + (10 m/s)(3 s) = 75 m

So the distance between the balloon and the parachutist after 3 s is

d = 75 m - 30.9 m = 44.1 m

(c) 8.2 m/s downward

The velocity of the parachutist at the moment he opens the parachute is:

v = u +gt

where

u = 10 m/s is the initial velocity (upward)

t is the time

g = -9.8 m/s^2 is the acceleration of gravity (downward)

Substituting t = 3 s,

v = 10 m/s + (-9.8 m/s^2)(3 s)= -19.4 m/s

where the negative sign means it is downward

After t=3 s, the parachutist open the parachute and it starts moving with a deceleration of

a =+5 m/s^2

where we put a positive sign since this time the acceleration is upward.

The total distance he still has to cover till the ground is

d = 30.9 m

So we can find the final velocity by using

v^2-u^2 = 2ad

where this time we have u = 19.4 m/s as initial velocity. Taking the downward direction as positive, the deceleration must be considered as negative:

a = -5 m/s^2

Solving for v,

v=\sqrt{u^2 +2ad}=\sqrt{(19.4 m/s)^2+2(-5 m/s^2)(30.9 m)}=8.2 m/s

(d) 5.24 s

We can find the duration of the second part of the motion of the parachutist (after he has opened the parachute) by using

a=\frac{v-u}{t}

where

a = -5 m/s^2 is the deceleration

v = 8.2 m/s is the final velocity

u = 19.4 m/s is the initial velocity

t is the time

Solving for t, we find

t=\frac{v-u}{a}=\frac{8.2 m/s-19.4 m/s}{-5 m/s^2}=2.24 s

And added to the 3 seconds between the instant of the jump and the moment he opens the parachute, the total time is

t = 3 s + 2.24 s = 5.24 s

8 0
2 years ago
What best describes the states of nonmetals when they are at room temperature? Most nonmetals are gaseous, but some are liquid o
abruzzese [7]
I think the correct answer from the choices listed above is the first option. The statement that best describes the state of metals when they are at room temperature would be that most <span>nonmetals are gaseous, but some are liquid or solid. Hope this answers the question. Have a nice day.</span>
3 0
3 years ago
Read 2 more answers
Estimate the radiation pressure due to a bulb that emits 25 W of EM radiation at a distance of 9.5 cm from the center of the bul
MA_775_DIABLO [31]

Given Information:  

Power of bulb = w = 25 W atts

distance = d = 9.5 cm = 0.095 m

Required Information:  

Radiation Pressure = ?

Answer:

Radiation Pressure =7.34x10⁻⁷ N/m²

Explanation:

We know that radiation pressure is given by

P = I/c

Where I is the intensity of radiation and is given by

I = w/4πd²

Where w is the power of the bulb in watts and d is the distance from the center of the bulb.

So the radiation pressure becomes

P = w/c4πd²

Where c = 3x10⁸ m/s is the speed of light

P = 25/(3x10⁸*4*π*0.095²)

P = 7.34x10⁻⁷ N/m²

Therefore, the radiation pressure due to a 25 W bulb at a distance of 9.5 cm from the center of the bulb is 7.34x10⁻⁷ N/m²

4 0
2 years ago
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