Answer: it started too rot over time mold over time and decay and if you cooked a apple it would melt like ice cream cause of the heat waves and if the apple is surrounded by air i think what would happen it would still rot I guess but i wouldnt know for sure cause things with air take time too rot and things with air rot faster and slicing the apple into more pieces would make it decay or rot or mold faster cause its open and accepting everything it sees like bacteria bugs all that
Explanation: like the longer a apple is left half open it starts too rot then mold over time getting all bad and not good too eat or decay
read it all the stuff is in there i think
Answer:
It's B
Explanation:
A is going to evaporate more quickly causing it to push through the tube to beaker B.
Answer:
- <em>The mystery substance is</em> <u>C. Bromine (Br) </u>
Explanation:
<em>Argon (Ar) </em>is a noble gas. Whose freezing point is -189 °C (very low), thus it cannot be the frozen substance. Also, it is not reactive, thus is would have not reacted with iron. Hence, argon is not the mystery substance.
<em>Scandium (Sc) </em>is a metal from group 3 of the periodic table, thus is will not react with iron. Thus, scandium is not the mystery substance.
Both <em>bromine</em> and <em>iodine</em> are halogens (group 17 of the periodic table).
The freezing point of bromine is −7.2 °C, and the freezing point of iodine is 113.7 °C. Thus, both could be solids (frozen) in the lab.
The reactivity of the halogens decrease from top to bottom inside the group. Bromine is above iodine. Then bromine is more reactive than iodine.
Bromine is reactive enough to react with iron. Iodine is not reactive enough to react with iron.
You can find in the internet that bromine vapour over hot iron reacts producing iron(III) bromide. Also, that bromine vapors are red-brown.
Therefore, <em>the mystery substance is bromine (Br).</em>
Answer:
The correct answer is HCl
Explanation:
There is a dipole-dipole force in hydrochloric acid (HCl), this type of attraction occurs in polar covalent molecules. In this case, the positive end of the molecule (H) attracts the negative (Cl).