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Colt1911 [192]
3 years ago
14

Why are funeral home adding dining facilities to the business

Engineering
1 answer:
Gelneren [198K]3 years ago
5 0
Because they think it will make them more money
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A 10-mm-diameter Brinell hardness indenter produced an indentation 1.55 mm in diameter in a steel alloy when a load of 500 kg wa
BigorU [14]

Answer:

HB = 3.22

Explanation:

The formula to calculate the Brinell Hardness is given as follows:

HB = \frac{2P}{\pi D\sqrt{D^{2}- d^{2} } }

where,

HB = Brinell Hardness = ?

P = Applied Load in kg = 500 kg

D = Diameter of Indenter in mm = 10 mm

d = Diameter of the indentation in mm = 1.55 mm

Therefore, using these values, we get:

HB = \frac{(2)(500)}{\pi (10)\sqrt{10^{2}- 1.55^{2} } }

<u>HB = 3.22 </u>

4 0
3 years ago
Movimiento
goblinko [34]

wth u should clear ur question

5 0
3 years ago
The council members of a small town have decided that an earth levee should be rebuilt and strengthen to protect against future
Ket [755]

Answer:

present cost = $302218.15

Explanation:

given data

cost of the work 1st year A1  = $100,000

cost of the work 2nd year A2 = $85,000

cost of the work 3rd year A3 = $70,000

cost of the work 4th year A4 = $55,000

cost of the work 5th year A4 = $40,000

interest rate r = 6% = 0.06

to find out

present worth cost is for the first 5 years

solution

present worth cost will be here as per given equation

present cost = \frac{A1}{(1+r)^1}+ \frac{A2}{(1+r)^2} + \frac{A3}{(1+r)^3} + \frac{A4}{(1+r)^4}+ \frac{A5}{(1+r)^5}     .........................1

here r is rate of interest and A is amount given

put here value we get

present cost = \frac{100,000}{(1+0.06)^1}+ \frac{85,000}{(1+0.06)^2} + \frac{70,000}{(1+0.06)^3} + \frac{55,000}{(1+0.06)^4}+ \frac{40,000}{(1+0.06)^5}  

present cost = $302218.15

5 0
4 years ago
When driving during the daytime in reduced visibility, such as rain, smoke, or fog,
riadik2000 [5.3K]

Answer:A

Explanation:

3 0
3 years ago
Can you determine the critical distance along a flat surface?
Keith_Richards [23]

Explanation:

Consider a fluid of density, ρ moving with a velocity, U over a flat plate of length, L.

Let the Kinematic viscosity of the fluid be ν.

Let the flow over the fluid be laminar for a distance x from the leading edge.

Now this distance is called the critical distance.

Therefore, for a laminar flow, the critical distance can be defined as the distance from the leading edge of the plate where the Reynolds number is equal to 5 x 10^{5}

And Reynolds number is a dimensionless number which determines whether a flow is laminar or turbulent.  

Mathematically, we can write,

    Re = \frac{\rho .U.x}{\mu }

or 5 x 10^{5} =  \frac{\rho .U.x}{\mu } ( for a laminar flow )

Therefore, critical distance

x=\frac{5\times 10^{5}\times \mu }{\rho \times U}

So x is defined as the critical distance upto which the flow is laminar.

6 0
3 years ago
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