Answer:
= 7.02 ° C
Explanation:
The liquid water gives heat to melt the ice (Q₁) maintaining the temperature of 0 ° C and then the two waters are equilibrated to a final temperature.
Let's start by calculating the heat needed to melt the ice
Q₁ = m L
Q₁ = 0.090 3.33 10⁵
Q₁ = 2997 10⁴ J
This is the heat needed to melt all the ice
Now let's calculate at what temperature the water reaches when it releases this heat
Q = M 
(T₀ -)
Q₁ = Q
= T₀ - Q₁ / M
= 20.0 - 2997 104 / (0.600 4186)
= 20.0 - 11.93
= 8.07 ° C
This is the temperature of the water when all the ice is melted
Now the two bodies of water exchange heat until they reach an equilibrium temperature
Temperatures are
Water of greater mass T₀₂ = 8.07ºC
Melted ice T₀₁ = 0ºC
M (T₀₂ - ) = m ( - T₀₁)
M T₀₂ + m T₀₁ = m + M
= (M T₀₂ + 0) / (m + M)
= M / (m + M) T₀₂
let's calculate
= 0.600 / (0.600 + 0.090) 8.07
= 7.02 ° C
Diameter of objective lens = 1.22m
Wavelength of light = 4000Å
We have to find resolving power of telescope ..
★ Resolving power of telescope is given by
RP = D/1.22λ
- D denotes diameter of lens
- λ denotes wavelength of light
RP = D/1.22λ
RP = (1.22×10⁷)/(1.22×4)
RP = 0.25 × 10⁷
RP = 2.5 × 10⁶
★ Resolving power of microscope is given by
RP = 2μsinθ/λ
Answer: TheTroposphere contains 80% of the total gas in the atmosphere
To solve this problem it is necessary to apply the concepts related to intensity as a function of power and area.
Intensity is defined to be the power per unit area carried by a wave. Power is the rate at which energy is transferred by the wave. In equation form, intensity I is
The area of a sphere is given by
So replacing we have to
Since the question tells us to find the proportion when
So considering the two intensities we have to
The ratio between the two intensities would be
The power does not change therefore it remains constant, which allows summarizing the expression to
Re-arrange to find 
Therefore the intensity at five times this distance from the source is 
