<span>Answer:
To determine hybridization you count the # of un-bonded PAIR of electrons. Theny you count bonded domains (a double bond still counts as one bonded domain, so does a triple bond).
For the first Carbon on top, you see it bonded to 2 oxygens and 1 carbon.However, when you count up the valence electrons that would be present, there is supposed to be 2 more electrons (ONE electron pair) on carbon. To do hybridization you must also be familiar with drawing lewis structures. So when you draw the pair of un-bonded electrons on carbon, you see that there is ONE un-bonded electron pair, and THREE bonded domains.
ONE plus THREE = FOUR.
so that would be sp3.</span>
Its either b or c, but i think its b
Answer:
ClO⁻ + HC₂H₃O₂ ⇄ HClO + C₂H₃O₂⁻
Explanation:
Sodium hypochlorite is a strong electrolyte that ionizes in sodium cation and hypochlorite anion.
NaClO(aq) ⇒ Na⁺(aq) + ClO⁻(aq)
ClO⁻ is a base that reacts with acetic acid (HC₂H₃O₂) from vinegar (neutralization reaction).
ClO⁻ + HC₂H₃O₂ ⇄ HClO + C₂H₃O₂⁻
Need be in english because I don’t understand spanish
Answer:
15.9 grams of copper is produced
Explanation:
Step 1: Data given
Volume of hydrogen = 5.60 L ( at STP)
Step 2: The balanced equation
CuO (s) + H2 (g) → Cu (s) + H2O (g)
Step 3: Calculate moles H2
22.4 L = 1 mol
5.60 L = 0.25 moles
Step 3: Calculate moles Cu
For 1 mol CuO we need 1 mol H2 to produce 1 mol Cu and 1 mol H2O
For 0.25 moles H2 we'll have 0.25 moles Cu
Step 4: Calculate mass Cu
Mass Cu = moles Cu * molar mass Cu
Mass Cu = 0.25 moles * 63.546 g/mol
Mass Cu = 15.9 grams
15.9 grams of copper is produced