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Jlenok [28]
2 years ago
11

3. The doctor notices that Janet has long fingernails, and comments that fingernails grow at a rate (or

Chemistry
1 answer:
Viktor [21]2 years ago
6 0

Answer:

7.93 × 10⁻¹³ km/s

Explanation:

Step 1: Given data

Rate of growth of the fingernails (r): 2.50 cm/year

Step 2: Convert "r" from cm/year to km/year

We will use the following conversion factors.

  • 1 m = 100 cm
  • 1 km = 1000 m

\frac{2.50cm}{year} \times \frac{1m}{100cm} \times \frac{1km}{1000m} = 2.50 \times 10^{-5} km/year

Step 3: Convert "r" from km/year to km/s

We will use the following conversion factors.

  • 1 year = 365 day
  • 1 day = 24 h
  • 1 h = 60 min
  • 1 min = 60 s

\frac{2.50 \times 10^{-5} km}{year} \times \frac{1year}{365day} \times \frac{1day}{24h} \times \frac{1h}{60min} \times \frac{1min}{60s} = 7.93 \times 10^{-13} km/s

2.50 cm/year is equal to 7.93 × 10⁻¹³ kilometers/second.

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Ionic crystals are hard because of tight packing lattices, say, the positive and negative ions are strongly attached among themselves.
3 0
3 years ago
The normal boiling point of a liquid is 282 °C. At what temperature (in
ElenaW [278]

Answer:

The temperature at which the liquid vapor pressure will be 0.2 atm = 167.22 °C

Explanation:

Here we make use of the Clausius-Clapeyron equation;

ln\left (\frac{p_{2}}{p_{1}}  \right )=-\frac{\Delta H_{vap}}{R}\cdot \left (\frac{1}{T_{2}}-\frac{1}{T_{1}}  \right )

Where:

P₁ = 1 atm =The substance vapor pressure at temperature T₁ = 282°C = 555.15 K

P₂ = 0.2 atm = The substance vapor pressure at temperature T₂

\Delta H_{vap} = The heat of vaporization = 28.5 kJ/mol

R = The universal gas constant = 8.314 J/K·mol

Plugging in the above values in the Clausius-Clapeyron equation, we have;

ln\left (\frac{0.2}{1}  \right )=-\frac{28.5 \times 10^3}{8.3145}\cdot \left (\frac{1}{T_{2}}-\frac{1}{555.15}  \right )

\therefore T_2 = \frac{-3427.95}{ln(0.2)-6.175}

T₂ = 440.37 K

To convert to Celsius degree temperature, we subtract 273.15 as follows

T₂ in °C = 440.37 - 273.15 = 167.22 °C

Therefore, the temperature at which the liquid vapor pressure will be 0.2 atm = 167.22 °C.

5 0
3 years ago
Identify the hybridization of the c atom in ch2br2.
Oliga [24]
Hello!

The hybridization of the C atom in CH₂Br₂ is sp3

When bonding, the orbitals "s" and "p" from C atoms interact to form hybridized orbitals. If the C atom has 4 sigma bonds, as is the case in CH₂Br₂, there are 4 hybridized orbitals required, so 1 "s" orbital and 3 "p" orbitals hybridize to form an sp3 hybrid orbital. This orbital has tetrahedral geometry and the bond angle is 109,5 °.

Have a nice day!
7 0
3 years ago
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The molar mass of glucose is 180 grams per mole (g/mol). Which of the following procedures should you carry out to make a 1 M so
Strike441 [17]

Answer:

You need to dissolve 144 gr of glucose in 0.8 liters of water to have a 1 M solution.

Explanation:

Molarity is the amount of moles per liter of solution --> moles/liters. We are trying to get a 1 molar solution and we also know the liters (0,8L) so

1\frac {moles-of-glucose}{liters-of-water} =\frac{X moles-of-glucose}{0.8 liters-of-water} \\

1\frac{Moles-of-glucose}{liters-of-water } * 0.8 liters of water

after canceling liters of water you get 0,8 moles of glucose.

180 \frac{grams-of-glucose}{mol-of-glucose}*0.8 mol- of- glucose=144 grams-of-glucose

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CHM 17 Practice Final Exam
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