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Nata [24]
3 years ago
14

Please Balanced this Equation

Chemistry
1 answer:
Scilla [17]3 years ago
7 0

Answer:

\rm {Cr_2O_7}^{2-} + 6 \; Fe^{2+} + \underbrace{\rm 14\; H^{+}}_{\text{From}\atop \text{Acid}}\to 2\; Cr^{3+} + 6\; Fe^{3+} + 7\; H_2 O.

Explanation:

Consider the oxidation state on each of the element:

Left-hand side:

  • O: -2 (as in most compounds);
  • Cr: \displaystyle \frac{1}{2}(\underbrace{-2}_{\text{ion}} - \underbrace{7\times (-2)}_{\text{Oxygen}}) = +6;
  • Fe: +2 (from the charge of the ion);

Right-hand side:

  • Cr: +3;
  • Fe: +3.

Change in oxidation state:

  • Each Cr atom: decreases by 3 (reduction).
  • Each Fe atom: increases by 1 (oxidation).

Changes in oxidation states shall balance each other in redox reactions. Thus, for each Cr atom on the left-hand side, there need to be three Fe atoms.

Assume that the coefficient of the most complex species \rm Cr_2O_7^{2-} is 1. There will be two Cr atoms and hence six Fe atoms on the left-hand side. Additionally, there are going to be seven O atoms.

Atoms are conserved in chemical reactions. As a result, the right-hand side of this equation will contain

  • two Cr atoms,
  • six Fe atoms, and
  • seven O atoms.

O atoms seldom appear among the products in acidic environments; they rapidly combine with \rm H^{+} ions to produce water \rm H_2O. Seven O atoms will make seven water molecules. That's fourteen H atoms and hence fourteen \rm H^{+} ions on the product side of this equation. Hence the balanced equation. Double check to ensure that the charges on the ions also balance.

\rm {Cr_2O_7}^{2-} + 6 \; Fe^{2+} + \underbrace{\rm 14\; H^{+}}_{\text{From}\atop \text{Acid}}\to 2\; Cr^{3+} + 6\; Fe^{3+} + 7\; H_2 O.

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<u>Explanation:</u>

Solubility is defined as the maximum amount of solute that can be dissolved in a solvent at equilibrium.

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

The balanced equilibrium reaction for the ionization of calcium fluoride follows:

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The expression for solubility constant for this reaction will be:

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We are given:

K_{sp}=7.9\times 10^{-9}

Putting values in above equation, we get:

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