Answer:
F = - 1,598 10⁻³ N
Explanation:
Electic strength is given by Coulomb's law
F = k q₁ q₂ / r²
Where k is the Coulomb constant that is worth 8.99 10⁸ N m²/C², q₁ and q₂ are the charges and r is the distance that separates the electric charges
In this case the charge of the two spheres is the same and of a different sign since when you remove the charge of a sphere that was initially neutral, it is left with that charge removed but of the opposite sign
q₁ = q₂ = 2.50 10¹³ electrons = 2.50 10¹³ 1.6 10⁻¹⁹
q₀ = 4.0 10⁻⁶ C
Let's calculate
F = - 8.99 10⁸ (4.0 10⁻⁶)² / 0.30²
F = - 1,598 10⁻³ N
The impulse exerted by a force F on an object in a time

is given by

In our problem, we have a force of 120 N: F=120 N, applied to the baseball for a time of

. Therefore the impulse is
Answer:
<h3>The answer is 144 g</h3>
Explanation:
The mass of a substance when given the density and volume can be found by using the formula
<h3>mass = Density × volume</h3>
From the question
volume = 78.0 mL
density = 1.85 g/mL
We have
mass = 78 × 1.85 = 144.3
We have the final answer as
<h3>144 g</h3>
Hope this helps you
Answer:
41.38
Explanation: You take the 3.14 and multiply it with the
Answer:
The transmitted intensity through all polarizers = 34.73
Explanation:
Given :
Incident intensity = 
Angle between the transmission axis and polarizer optic axis = 18°
According to the malus law, when unpolarized or polarized light passes through polarizing disk, the intensity of the transmitted light is directly proportional to the square of the cosine of angle between the transmission axis and polarizer optic axis.
∴ 
Where
transmitted intensity,
incident intensity,
angle between the transmission axis and polarizer optic axis.
Here, there are four polarizing disks so that.
from first disk,
∴
₁
18°
=
×
= 
Now
₁ behave as an incident light for second polarizer so we only multiply
term
so we write,
∴
₂ =
×

From third polarizer,
∴
₃ =
×

From forth polarizer,
∴
₄ =
×

Therefor, the the transmitted intensity through forth polarizer = 34.73
.